RE: BOV
From:"Pravin" jadhavpr@mail1.vcu.edu
Subject: RE: [NMusers] BOV
Date: Tue, September 21, 2004 12:36 pm
Dear all,
After I look at Nick's answer I realize that I have made a basic
mistake in my derivation. Please interpret it carefully. Discussion
with Dr. Yaning Wang made it clearer to me. The derivation provided is
true in general sense but needs explanation while using it when we
have two levels of randomness(BSV and BOV).
Nick used a case when BOV is the same at all occasions.
%CV of Pi = SQRT(BSV*BSV + BOV*BOV)*100
Let's say it is not (rare but consider for theoretical purposes), then
we can add up variances but Pi needs to grouped according to
occasions.
Given Occasion 1: %CV of Pi = SQRT(BSV*BSV + BOV(1)*BOV(1))*100
Given Occasion 2: %CV of Pi = SQRT(BSV*BSV + BOV(2)*BOV(2))*100
....
Given Occasion n: %CV of Pi = SQRT(BSV*BSV + BOV(n)*BOV(n))*100
I hope I did not create any confusion. Sorry for any inconvenience.
Thanks,
Pravin
Pravin Jadhav