Hi all, to calculate AUC of one of the compartments using ADVAN6, if it is a
fixed time interval, will the AUC be influenced by the frequncy of sampling of
the dataset within this interval or not?
thanks
calculation of AUC
12 messages
7 people
Latest: Mar 26, 2009
I second Bill's suggestion to work this out on your own for your specific
problem. This forum can help you with general questions and overall
approaches, but very specific queries like this are for you and your
colleagues to hash out.
----- Forwarded by Michael J Fossler/PharmRD/GSK on 03/20/2009 09:40 AM
-----
"Bill Bachman" <bachmanw
Sent by: owner-nmusers
20-Mar-2009 09:17
To
"'Martin Bergstrand'" <martin.bergstrand
<ethan.wu75
cc
Subject
RE: [NMusers] calculation of AUC
The easiest answer is to work it out. Do some simulations (without
variability) with multiple subjects with identical PK parameters BUT
different sampling times. Tabulate your AUCs and compare the results for
different sampling times!
Quoted reply history
From: owner-nmusers
On Behalf Of Martin Bergstrand
Sent: Friday, March 20, 2009 8:45 AM
To: 'Ethan Wu'; nmusers
Subject: RE: [NMusers] calculation of AUC
Dear Ethan,
You need to provide more information on how you plan to calculate AUC
otherwise the question can?t be answered. It is of course possible to
calculate the AUC without any influence of the sampling frequency. You
should be able to find examples of how to do this in the NMusers archive.
See for example the answer from Mats Karlsson in this thread (
http://nonmem.org/nonmem/nm/98apr032002.html).
Kind regards,
Martin Bergstrand, MSc, PhD student
-----------------------------------------------
Department of Pharmaceutical Biosciences,
Uppsala University
-----------------------------------------------
P.O. Box 591
SE-751 24 Uppsala
Sweden
-----------------------------------------------
martin.bergstrand
-----------------------------------------------
Work: +46 18 471 4639
Mobile: +46 709 994 396
Fax: +46 18 471 4003
From: owner-nmusers
On Behalf Of Ethan Wu
Sent: den 20 mars 2009 13:05
To: nmusers
Subject: [NMusers] calculation of AUC
Hi all, to calculate AUC of one of the compartments using ADVAN6, if it is
a fixed time interval, will the AUC be influenced by the frequncy of
sampling of the dataset within this interval or not?
thanks
No viruses found in this incoming message
Scanned by iolo AntiVirus 1.5.6.4
http://www.iolo.com
(image/jpeg attachment: 01-part)
Dear Ethan,
You need to provide more information on how you plan to calculate AUC
otherwise the question can't be answered. It is of course possible to
calculate the AUC without any influence of the sampling frequency. You
should be able to find examples of how to do this in the NMusers archive.
See for example the answer from Mats Karlsson in this thread
( http://nonmem.org/nonmem/nm/98apr032002.html).
Kind regards,
Martin Bergstrand, MSc, PhD student
-----------------------------------------------
Department of Pharmaceutical Biosciences,
Uppsala University
-----------------------------------------------
P.O. Box 591
SE-751 24 Uppsala
Sweden
-----------------------------------------------
<mailto:[email protected]> [email protected]
-----------------------------------------------
Work: +46 18 471 4639
Mobile: +46 709 994 396
Fax: +46 18 471 4003
Quoted reply history
From: [email protected] [mailto:[email protected]] On
Behalf Of Ethan Wu
Sent: den 20 mars 2009 13:05
To: [email protected]
Subject: [NMusers] calculation of AUC
Hi all, to calculate AUC of one of the compartments using ADVAN6, if it is a
fixed time interval, will the AUC be influenced by the frequncy of sampling
of the dataset within this interval or not?
thanks
The easiest answer is to work it out. Do some simulations (without
variability) with multiple subjects with identical PK parameters BUT
different sampling times. Tabulate your AUCs and compare the results for
different sampling times!
_____
Quoted reply history
From: [email protected] [mailto:[email protected]] On
Behalf Of Martin Bergstrand
Sent: Friday, March 20, 2009 8:45 AM
To: 'Ethan Wu'; [email protected]
Subject: RE: [NMusers] calculation of AUC
Dear Ethan,
You need to provide more information on how you plan to calculate AUC
otherwise the question can't be answered. It is of course possible to
calculate the AUC without any influence of the sampling frequency. You
should be able to find examples of how to do this in the NMusers archive.
See for example the answer from Mats Karlsson in this thread
( http://nonmem.org/nonmem/nm/98apr032002.html).
Kind regards,
Martin Bergstrand, MSc, PhD student
-----------------------------------------------
Department of Pharmaceutical Biosciences,
Uppsala University
-----------------------------------------------
P.O. Box 591
SE-751 24 Uppsala
Sweden
-----------------------------------------------
<mailto:[email protected]> [email protected]
-----------------------------------------------
Work: +46 18 471 4639
Mobile: +46 709 994 396
Fax: +46 18 471 4003
From: [email protected] [mailto:[email protected]] On
Behalf Of Ethan Wu
Sent: den 20 mars 2009 13:05
To: [email protected]
Subject: [NMusers] calculation of AUC
Hi all, to calculate AUC of one of the compartments using ADVAN6, if it is a
fixed time interval, will the AUC be influenced by the frequncy of sampling
of the dataset within this interval or not?
thanks
_____
No viruses found in this incoming message
Scanned by iolo AntiVirus 1.5.6.4
http://www.iolo.com http://www.iolo.com/iav/iavpop3
I second Bill's suggestion to work this out on your own for your specific
problem. This forum can help you with general questions and overall
approaches, but very specific queries like this are for you and your
colleagues to hash out.
----- Forwarded by Michael J Fossler/PharmRD/GSK on 03/20/2009 09:40 AM
-----
"Bill Bachman" <[email protected]>
Sent by: [email protected]
20-Mar-2009 09:17
To
"'Martin Bergstrand'" <[email protected]>, "'Ethan Wu'"
<[email protected]>, [email protected]
cc
Subject
RE: [NMusers] calculation of AUC
The easiest answer is to work it out. Do some simulations (without
variability) with multiple subjects with identical PK parameters BUT
different sampling times. Tabulate your AUCs and compare the results for
different sampling times!
Quoted reply history
From: [email protected] [mailto:[email protected]]
On Behalf Of Martin Bergstrand
Sent: Friday, March 20, 2009 8:45 AM
To: 'Ethan Wu'; [email protected]
Subject: RE: [NMusers] calculation of AUC
Dear Ethan,
You need to provide more information on how you plan to calculate AUC
otherwise the question can?t be answered. It is of course possible to
calculate the AUC without any influence of the sampling frequency. You
should be able to find examples of how to do this in the NMusers archive.
See for example the answer from Mats Karlsson in this thread (
http://nonmem.org/nonmem/nm/98apr032002.html).
Kind regards,
Martin Bergstrand, MSc, PhD student
-----------------------------------------------
Department of Pharmaceutical Biosciences,
Uppsala University
-----------------------------------------------
P.O. Box 591
SE-751 24 Uppsala
Sweden
-----------------------------------------------
[email protected]
-----------------------------------------------
Work: +46 18 471 4639
Mobile: +46 709 994 396
Fax: +46 18 471 4003
From: [email protected] [mailto:[email protected]]
On Behalf Of Ethan Wu
Sent: den 20 mars 2009 13:05
To: [email protected]
Subject: [NMusers] calculation of AUC
Hi all, to calculate AUC of one of the compartments using ADVAN6, if it is
a fixed time interval, will the AUC be influenced by the frequncy of
sampling of the dataset within this interval or not?
thanks
No viruses found in this incoming message
Scanned by iolo AntiVirus 1.5.6.4
http://www.iolo.com
<<image/jpeg>>
Dear Ethan,
Just a caution when comparing model-based AUCs with NCA calculated AUCs. If you
have done your modeling using log-transformation of observations and model
predictions and then compared AUCs on the linear scale, you should not expect a
perfect agreement between the two. The reason is that the mean of an
exponentiated distribution of epsilons is not the same as the median, but
higher. Thus, the AUCs of model-predicted individual profiles will be expected
to be lower than either simulated or observed. The magnitude of the difference
will depend on the residual error magnitude and will typically be:
%RV expected AUC difference
10 0.50%
20 2%
30 5%
40 9%
50 14%
70 29%
Best regards,
Mats
Mats Karlsson, PhD
Professor of Pharmacometrics
Dept of Pharmaceutical Biosciences
Uppsala University
Box 591
751 24 Uppsala Sweden
phone: +46 18 4714105
fax: +46 18 471 4003
Quoted reply history
From: [email protected] [mailto:[email protected]] On
Behalf Of Ethan Wu
Sent: Friday, March 20, 2009 6:52 PM
To: [email protected]; [email protected]
Subject: Re: [NMusers] calculation of AUC
sorry for being lazy this morning and wish relying on others knowledge
just to share, I used DADT=C method, and it didn't depend on sampling after I
tried with my model (which took quite a while to get results)
-- I could do as Bill suggested setting up some small dataset and simple model
to check first, then would share with the group ealier :-)
_____
From: "[email protected]" <[email protected]>
To: [email protected]
Sent: Friday, March 20, 2009 9:42:59 AM
Subject: Fw: [NMusers] calculation of AUC
I second Bill's suggestion to work this out on your own for your specific
problem. This forum can help you with general questions and overall approaches,
but very specific queries like this are for you and your colleagues to hash
out.
Error! Filename not specified.
----- Forwarded by Michael J Fossler/PharmRD/GSK on 03/20/2009 09:40 AM -----
"Bill Bachman" <[email protected]>
Sent by: [email protected]
20-Mar-2009 09:17
To
"'Martin Bergstrand'" <[email protected]>, "'Ethan Wu'"
<[email protected]>, [email protected]
cc
Subject
RE: [NMusers] calculation of AUC
The easiest answer is to work it out. Do some simulations (without
variability) with multiple subjects with identical PK parameters BUT different
sampling times. Tabulate your AUCs and compare the results for different
sampling times!
_____
From: [email protected] [mailto:[email protected]] On
Behalf Of Martin Bergstrand
Sent: Friday, March 20, 2009 8:45 AM
To: 'Ethan Wu'; [email protected]
Subject: RE: [NMusers] calculation of AUC
Dear Ethan,
You need to provide more information on how you plan to calculate AUC otherwise
the question can’t be answered. It is of course possible to calculate the AUC
without any influence of the sampling frequency. You should be able to find
examples of how to do this in the NMusers archive. See for example the answer
from Mats Karlsson in this thread (
http://nonmem.org/nonmem/nm/98apr032002.html
http://nonmem..org/nonmem/nm/98apr032002.html).
Kind regards,
Martin Bergstrand, MSc, PhD student
-----------------------------------------------
Department of Pharmaceutical Biosciences,
Uppsala University
-----------------------------------------------
P.O. Box 591
SE-751 24 Uppsala
Sweden
-----------------------------------------------
<mailto:[email protected]> [email protected]
-----------------------------------------------
Work: +46 18 471 4639
Mobile: +46 709 994 396
Fax: +46 18 471 4003
From: [email protected] [mailto:[email protected]] On
Behalf Of Ethan Wu
Sent: den 20 mars 2009 13:05
To: [email protected]
Subject: [NMusers] calculation of AUC
Hi all, to calculate AUC of one of the compartments using ADVAN6, if it is a
fixed time interval, will the AUC be influenced by the frequncy of sampling of
the dataset within this interval or not?
thanks
_____
No viruses found in this incoming message
Scanned by iolo AntiVirus 1.5.6.4
http://www.iolo.com/iav/iavpop3 http://www.iolo.com
Mats,
This is an interesting idea but it seems to be more complicated than just a consideration of the residual variability (RV%) when using log transformation with transform both sides (TBS) estimation.
First of all you appear to assume that the RV% is only a proportional residual error but if could also include an additive component when using TBS so that there is not a single RV% that would describe a particular situation because it would change with concentration.
A model based estimate of AUC would typically be based on an empirical Bayes estimate (EBE) of CL. This estimate is of course a shrinkage estimate which will typically be biased towards the population CL but I have realized that there is also EBE bias from the choice of transformation used in parameter estimation. Thus I would not expect the model based estimate to be additionally biased because of using EBEs with TBS. This is probably something you have thought about so please inform me.
Turning to the NCA method - I dont know if a bias is expected from the NCA calculated AUC but I would naively assume that the trapezoidal part would not be biased. I am ready to learn if there is a bias expected with trapezoidal NCA. I expect this has been investigated and reported but I am not familiar with it. The extrapolated portion typically relies on a log linear transformation to estimate the elimination rate constant which so in this respect the log transformed model based and NCA based methods would seem to be similar.
Another source of difference between model and NCA based AUCs might arise from the use of different statistics to describe the central tendency of the indidual estimates. NCA estimates could be based on the arithmetic mean of the individual AUC sor on the geometric mean (most commonly used for bioequivalence analysis). The model based estimates based on the arithmetic mean of the EBE predicted AUCs would be biased towards the geometric mean because the population value would typically be estimated with an exponential ETA.
If you have the time would you expand on the details of your assertion so that I and others can understand the basis more clearly? It seems to me that comparison of model based AUCs with NCA based AUCs is more complicated than just a consideration of the typical value of the residual error.
Nick
Mats Karlsson wrote:
> Dear Ethan,
>
> Just a caution when comparing model-based AUCs with NCA calculated AUCs. If you have done your modeling using log-transformation of observations and model predictions and then compared AUCs on the linear scale, you should not expect a perfect agreement between the two. The reason is that the mean of an exponentiated distribution of epsilons is not the same as the median, but higher. Thus, the AUCs of model-predicted individual profiles will be expected to be lower than either simulated or observed. The magnitude of the difference will depend on the residual error magnitude and will typically be:
>
> %RV expected AUC difference
>
> 10 0.50%
>
> 20 2%
>
> 30 5%
>
> 40 9%
>
> 50 14%
>
> 70 29%
>
> Best regards,
>
> Mats
>
> Mats Karlsson, PhD
>
> Professor of Pharmacometrics
>
> Dept of Pharmaceutical Biosciences
>
> Uppsala University
>
> Box 591
>
> 751 24 Uppsala Sweden
>
> phone: +46 18 4714105
>
> fax: +46 18 471 4003
>
> *From:* [email protected] [ mailto: [email protected] ] *On Behalf Of *Ethan Wu
>
> *Sent:* Friday, March 20, 2009 6:52 PM
> *To:* [email protected]; [email protected]
> *Subject:* Re: [NMusers] calculation of AUC
>
> sorry for being lazy this morning and wish relying on others knowledge
>
> just to share, I used DADT=C method, and it didn't depend on sampling after I tried with my model (which took quite a while to get results)
>
> -- I could do as Bill suggested setting up some small dataset and simple model to check first, then would share with the group ealier :-)
>
> ------------------------------------------------------------------------
>
> *From:* "[email protected]" <[email protected]>
> *To:* [email protected]
> *Sent:* Friday, March 20, 2009 9:42:59 AM
> *Subject:* Fw: [NMusers] calculation of AUC
>
> I second Bill's suggestion to work this out on your own for your specific problem. This forum can help you with general questions and overall approaches, but very specific queries like this are for you and your colleagues to hash out.
>
> *Error! Filename not specified.*
>
> ----- Forwarded by Michael J Fossler/PharmRD/GSK on 03/20/2009 09:40 AM -----
>
> *"Bill Bachman" <[email protected]>*
> Sent by: [email protected]
>
> 20-Mar-2009 09:17
>
> To
>
> "'Martin Bergstrand'" < [email protected] >, "'Ethan Wu'" < [email protected] >, [email protected]
>
> cc
>
> Subject
>
> RE: [NMusers] calculation of AUC
>
> The easiest answer is to work it out. Do some simulations (without variability) with multiple subjects with identical PK parameters BUT different sampling times. Tabulate your AUCs and compare the results for different sampling times!
>
> ------------------------------------------------------------------------
>
> *From:* [email protected] [ mailto: [email protected] ] *On Behalf Of *Martin Bergstrand*
>
> Sent:* Friday, March 20, 2009 8:45 AM*
> To:* 'Ethan Wu'; [email protected]*
> Subject:* RE: [NMusers] calculation of AUC
>
> Dear Ethan, You need to provide more information on how you plan to calculate AUC otherwise the question can’t be answered. It is of course possible to calculate the AUC without any influence of the sampling frequency. You should be able to find examples of how to do this in the NMusers archive. See for example the answer from Mats Karlsson in this thread ( http://nonmem..org/nonmem/nm/98apr032002.html < http://nonmem.org/nonmem/nm/98apr032002.html >). Kind regards, Martin Bergstrand, MSc, PhD student
>
> -----------------------------------------------
> Department of Pharmaceutical Biosciences,
> Uppsala University
> -----------------------------------------------
> P.O. Box 591
> SE-751 24 Uppsala
> Sweden
> -----------------------------------------------
> [email protected] <mailto:[email protected]>
> -----------------------------------------------
> Work: +46 18 471 4639
> Mobile: +46 709 994 396
> Fax: +46 18 471 4003
>
> *From:* [email protected] [ mailto: [email protected] ] *On Behalf Of *Ethan Wu*
>
> Sent:* den 20 mars 2009 13:05*
> To:* [email protected]*
> Subject:* [NMusers] calculation of AUC
>
> Hi all, to calculate AUC of one of the compartments using ADVAN6, if it is a fixed time interval, will the AUC be influenced by the frequncy of sampling of the dataset within this interval or not?
>
> thanks
>
> ------------------------------------------------------------------------
>
> No viruses found in this incoming message
> Scanned by *iolo AntiVirus 1.5.6.4*_
> _ http://www.iolo.com http://www.iolo.com/iav/iavpop3
--
Nick Holford, Dept Pharmacology & Clinical Pharmacology
University of Auckland, 85 Park Rd, Private Bag 92019, Auckland, New Zealand
[email protected] tel:+64(9)923-6730 fax:+64(9)373-7090
http://www.fmhs.auckland.ac.nz/sms/pharmacology/holford
Dear Nick,
I did not discuss shrinkage because it didn't concern the point I was trying
(and maybe failing) to make. [However, I don't think that if one wants to
compare with NCA AUCs, data are likely to be rich with reasonably small
shrinkage]
I used proportional residual error as an example. Doesn't really matter which
residual error you use - going from the normality assumption on the log scale
to normal scale would always make the mean of a simulated observation higher
than the mean. Mean(exp(epsilon)) is going to be higher than 1 regardless of
residual error model.
The point I'm trying to make is not how you calculate the central tendency of
several AUCs, it concerns the calculation of individual AUCs.
The problem I point out is relevant when you compare NCA AUCs from observed
data with NCA AUCs from model predictions, regardless if you use linear or
log-linear trapezoidal rules. Observed NCA AUCs are expected to be higher than
NCA AUCs from model-predicted (but not higher than model simulated) AUCs
calculated by NCA (from the same sampling schedule).
For a model:
Y=LOG(F)+EPS(1)
The exponentiation of LOG(F) will give the expected mean of F [from which
model-predicted NCA AUC will be calculated]
The exponentiation of (LOG(F)+EPS(1)) will not give the expected mean of F, but
something higher. [this is what you can calculate model-simulated NCA AUCs from]
Thus model-predicted and model-simulated NCA AUCs will be systematically
different if they are calculated in this way. I expect that if the model is
correct, the observed NCA AUCs will be more similar to the simulated NCA AUCs.
Hope this makes it clearer.
Best regards,
Mats
Mats Karlsson, PhD
Professor of Pharmacometrics
Dept of Pharmaceutical Biosciences
Uppsala University
Box 591
751 24 Uppsala Sweden
phone: +46 18 4714105
fax: +46 18 471 4003
Quoted reply history
-----Original Message-----
From: [email protected] [mailto:[email protected]] On
Behalf Of Nick Holford
Sent: Sunday, March 22, 2009 7:09 AM
To: nmusers
Subject: Re: [NMusers] calculation of AUC
Mats,
This is an interesting idea but it seems to be more complicated than
just a consideration of the residual variability (RV%) when using log
transformation with transform both sides (TBS) estimation.
First of all you appear to assume that the RV% is only a proportional
residual error but if could also include an additive component when
using TBS so that there is not a single RV% that would describe a
particular situation because it would change with concentration.
A model based estimate of AUC would typically be based on an empirical
Bayes estimate (EBE) of CL. This estimate is of course a shrinkage
estimate which will typically be biased towards the population CL but I
have realized that there is also EBE bias from the choice of
transformation used in parameter estimation. Thus I would not expect the
model based estimate to be additionally biased because of using EBEs
with TBS. This is probably something you have thought about so please
inform me.
Turning to the NCA method - I dont know if a bias is expected from the
NCA calculated AUC but I would naively assume that the trapezoidal part
would not be biased. I am ready to learn if there is a bias expected
with trapezoidal NCA. I expect this has been investigated and reported
but I am not familiar with it. The extrapolated portion typically relies
on a log linear transformation to estimate the elimination rate constant
which so in this respect the log transformed model based and NCA based
methods would seem to be similar.
Another source of difference between model and NCA based AUCs might
arise from the use of different statistics to describe the central
tendency of the indidual estimates. NCA estimates could be based on the
arithmetic mean of the individual AUC sor on the geometric mean (most
commonly used for bioequivalence analysis). The model based estimates
based on the arithmetic mean of the EBE predicted AUCs would be biased
towards the geometric mean because the population value would typically
be estimated with an exponential ETA.
If you have the time would you expand on the details of your assertion
so that I and others can understand the basis more clearly? It seems to
me that comparison of model based AUCs with NCA based AUCs is more
complicated than just a consideration of the typical value of the
residual error.
Nick
Mats Karlsson wrote:
>
> Dear Ethan,
>
>
>
> Just a caution when comparing model-based AUCs with NCA calculated
> AUCs. If you have done your modeling using log-transformation of
> observations and model predictions and then compared AUCs on the
> linear scale, you should not expect a perfect agreement between the
> two. The reason is that the mean of an exponentiated distribution of
> epsilons is not the same as the median, but higher. Thus, the AUCs of
> model-predicted individual profiles will be expected to be lower than
> either simulated or observed. The magnitude of the difference will
> depend on the residual error magnitude and will typically be:
>
>
>
> %RV expected AUC difference
>
> 10 0.50%
>
> 20 2%
>
> 30 5%
>
> 40 9%
>
> 50 14%
>
> 70 29%
>
>
>
> Best regards,
>
> Mats
>
>
>
> Mats Karlsson, PhD
>
> Professor of Pharmacometrics
>
> Dept of Pharmaceutical Biosciences
>
> Uppsala University
>
> Box 591
>
> 751 24 Uppsala Sweden
>
> phone: +46 18 4714105
>
> fax: +46 18 471 4003
>
>
>
> *From:* [email protected]
> [mailto:[email protected]] *On Behalf Of *Ethan Wu
> *Sent:* Friday, March 20, 2009 6:52 PM
> *To:* [email protected]; [email protected]
> *Subject:* Re: [NMusers] calculation of AUC
>
>
>
> sorry for being lazy this morning and wish relying on others knowledge
>
> just to share, I used DADT=C method, and it didn't depend on sampling
> after I tried with my model (which took quite a while to get results)
>
> -- I could do as Bill suggested setting up some small dataset and
> simple model to check first, then would share with the group ealier :-)
>
>
>
>
>
>
> ------------------------------------------------------------------------
>
> *From:* "[email protected]" <[email protected]>
> *To:* [email protected]
> *Sent:* Friday, March 20, 2009 9:42:59 AM
> *Subject:* Fw: [NMusers] calculation of AUC
>
>
> I second Bill's suggestion to work this out on your own for your
> specific problem. This forum can help you with general questions and
> overall approaches, but very specific queries like this are for you
> and your colleagues to hash out.
>
> *Error! Filename not specified.*
> ----- Forwarded by Michael J Fossler/PharmRD/GSK on 03/20/2009 09:40
> AM -----
>
> *"Bill Bachman" <[email protected]>*
> Sent by: [email protected]
>
> 20-Mar-2009 09:17
>
>
>
>
>
> To
>
>
>
> "'Martin Bergstrand'" <[email protected]>, "'Ethan Wu'"
> <[email protected]>, [email protected]
>
> cc
>
>
>
> Subject
>
>
>
> RE: [NMusers] calculation of AUC
>
>
>
>
>
>
>
>
>
> The easiest answer is to work it out. Do some simulations (without
> variability) with multiple subjects with identical PK parameters BUT
> different sampling times. Tabulate your AUCs and compare the results
> for different sampling times!
>
>
>
>
> ------------------------------------------------------------------------
>
>
> *From:* [email protected]
> [mailto:[email protected]] *On Behalf Of *Martin Bergstrand*
> Sent:* Friday, March 20, 2009 8:45 AM*
> To:* 'Ethan Wu'; [email protected]*
> Subject:* RE: [NMusers] calculation of AUC
>
> Dear Ethan,
>
> You need to provide more information on how you plan to calculate AUC
> otherwise the question can’t be answered. It is of course possible to
> calculate the AUC without any influence of the sampling frequency. You
> should be able to find examples of how to do this in the NMusers
> archive. See for example the answer from Mats Karlsson in this thread
> ( http://nonmem..org/nonmem/nm/98apr032002.html
> http://nonmem.org/nonmem/nm/98apr032002.html).
>
> Kind regards,
>
> Martin Bergstrand, MSc, PhD student
> -----------------------------------------------
> Department of Pharmaceutical Biosciences,
> Uppsala University
> -----------------------------------------------
> P.O. Box 591
> SE-751 24 Uppsala
> Sweden
> -----------------------------------------------
> [email protected] <mailto:[email protected]>
> -----------------------------------------------
> Work: +46 18 471 4639
> Mobile: +46 709 994 396
> Fax: +46 18 471 4003
>
>
> *From:* [email protected]
> [mailto:[email protected]] *On Behalf Of *Ethan Wu*
> Sent:* den 20 mars 2009 13:05*
> To:* [email protected]*
> Subject:* [NMusers] calculation of AUC
>
> Hi all, to calculate AUC of one of the compartments using ADVAN6, if
> it is a fixed time interval, will the AUC be influenced by the
> frequncy of sampling of the dataset within this interval or not?
> thanks
>
>
> ------------------------------------------------------------------------
>
> No viruses found in this incoming message
> Scanned by *iolo AntiVirus 1.5.6.4*_
> _ http://www.iolo.com http://www.iolo.com/iav/iavpop3
>
>
>
--
Nick Holford, Dept Pharmacology & Clinical Pharmacology
University of Auckland, 85 Park Rd, Private Bag 92019, Auckland, New Zealand
[email protected] tel:+64(9)923-6730 fax:+64(9)373-7090
http://www.fmhs.auckland.ac.nz/sms/pharmacology/holford
Mats,
Thanks for trying to explain things further but I am still confused. I agree for the moment we can forget about shrinkage and about computing the central tendency over a group of subjects.
Lets just fit one individual with a model and estimate clearance then calculate AUC from Dose/CL. If we take the same concentration observations and compute an AUC using a trapezoidal rule then I still dont follow your example.
You say:
"The exponentiation of (LOG(F)+EPS(1)) will not give the expected mean of F, but
something higher. [this is what you can calculate model-simulated NCA AUCs from]"
but I dont understand what you mean by "this is what you calculate model-simulate NCA AUCs from".
I am not thinking of calculating NCA AUCs from simulated concentrations. I expect to use real measured concentrations.
Simulating concentrations which force all concentrations to be non-negative is a biased simulation of reality. If there is any possibility of an additive error then there is a possibility of a negative measured concentration. Real assays can have additive errors so real assays must be capable of measuring values that appear to be negative. Note the difference between the true concentration which must be non-negative and the measured concentration, i.e. the truth plus error, which can be negative if the error is additive.
Nick
Mats Karlsson wrote:
> Dear Nick,
>
> I did not discuss shrinkage because it didn't concern the point I was trying
> (and maybe failing) to make. [However, I don't think that if one wants to
> compare with NCA AUCs, data are likely to be rich with reasonably small
> shrinkage]
>
> I used proportional residual error as an example. Doesn't really matter which
> residual error you use - going from the normality assumption on the log scale
> to normal scale would always make the mean of a simulated observation higher
> than the mean. Mean(exp(epsilon)) is going to be higher than 1 regardless of
> residual error model.
>
> The point I'm trying to make is not how you calculate the central tendency of
> several AUCs, it concerns the calculation of individual AUCs.
>
> The problem I point out is relevant when you compare NCA AUCs from observed data with NCA AUCs from model predictions, regardless if you use linear or log-linear trapezoidal rules. Observed NCA AUCs are expected to be higher than NCA AUCs from model-predicted (but not higher than model simulated) AUCs calculated by NCA (from the same sampling schedule). For a model:
>
> Y=LOG(F)+EPS(1)
> The exponentiation of LOG(F) will give the expected mean of F [from which
> model-predicted NCA AUC will be calculated]
> The exponentiation of (LOG(F)+EPS(1)) will not give the expected mean of F, but
> something higher. [this is what you can calculate model-simulated NCA AUCs from]
>
> Thus model-predicted and model-simulated NCA AUCs will be systematically different if they are calculated in this way. I expect that if the model is correct, the observed NCA AUCs will be more similar to the simulated NCA AUCs.
>
> Hope this makes it clearer.
>
> Best regards,
> Mats
>
> Mats Karlsson, PhD
> Professor of Pharmacometrics
> Dept of Pharmaceutical Biosciences
> Uppsala University
> Box 591
> 751 24 Uppsala Sweden
> phone: +46 18 4714105
> fax: +46 18 471 4003
>
Quoted reply history
> -----Original Message-----
> From: [email protected] [mailto:[email protected]] On
> Behalf Of Nick Holford
> Sent: Sunday, March 22, 2009 7:09 AM
> To: nmusers
> Subject: Re: [NMusers] calculation of AUC
>
> Mats,
>
> This is an interesting idea but it seems to be more complicated than just a consideration of the residual variability (RV%) when using log transformation with transform both sides (TBS) estimation.
>
> First of all you appear to assume that the RV% is only a proportional residual error but if could also include an additive component when using TBS so that there is not a single RV% that would describe a particular situation because it would change with concentration.
>
> A model based estimate of AUC would typically be based on an empirical Bayes estimate (EBE) of CL. This estimate is of course a shrinkage estimate which will typically be biased towards the population CL but I have realized that there is also EBE bias from the choice of transformation used in parameter estimation. Thus I would not expect the model based estimate to be additionally biased because of using EBEs with TBS. This is probably something you have thought about so please inform me.
>
> Turning to the NCA method - I dont know if a bias is expected from the NCA calculated AUC but I would naively assume that the trapezoidal part would not be biased. I am ready to learn if there is a bias expected with trapezoidal NCA. I expect this has been investigated and reported but I am not familiar with it. The extrapolated portion typically relies on a log linear transformation to estimate the elimination rate constant which so in this respect the log transformed model based and NCA based methods would seem to be similar.
>
> Another source of difference between model and NCA based AUCs might arise from the use of different statistics to describe the central tendency of the indidual estimates. NCA estimates could be based on the arithmetic mean of the individual AUC sor on the geometric mean (most commonly used for bioequivalence analysis). The model based estimates based on the arithmetic mean of the EBE predicted AUCs would be biased towards the geometric mean because the population value would typically be estimated with an exponential ETA.
>
> If you have the time would you expand on the details of your assertion so that I and others can understand the basis more clearly? It seems to me that comparison of model based AUCs with NCA based AUCs is more complicated than just a consideration of the typical value of the residual error.
>
> Nick
>
> Mats Karlsson wrote:
>
> > Dear Ethan,
> >
> > Just a caution when comparing model-based AUCs with NCA calculated AUCs. If you have done your modeling using log-transformation of observations and model predictions and then compared AUCs on the linear scale, you should not expect a perfect agreement between the two. The reason is that the mean of an exponentiated distribution of epsilons is not the same as the median, but higher. Thus, the AUCs of model-predicted individual profiles will be expected to be lower than either simulated or observed. The magnitude of the difference will depend on the residual error magnitude and will typically be:
> >
> > %RV expected AUC difference
> >
> > 10 0.50%
> >
> > 20 2%
> >
> > 30 5%
> >
> > 40 9%
> >
> > 50 14%
> >
> > 70 29%
> >
> > Best regards,
> >
> > Mats
> >
> > Mats Karlsson, PhD
> >
> > Professor of Pharmacometrics
> >
> > Dept of Pharmaceutical Biosciences
> >
> > Uppsala University
> >
> > Box 591
> >
> > 751 24 Uppsala Sweden
> >
> > phone: +46 18 4714105
> >
> > fax: +46 18 471 4003
> >
> > *From:* [email protected] [ mailto: [email protected] ] *On Behalf Of *Ethan Wu
> >
> > *Sent:* Friday, March 20, 2009 6:52 PM
> > *To:* [email protected]; [email protected]
> > *Subject:* Re: [NMusers] calculation of AUC
> >
> > sorry for being lazy this morning and wish relying on others knowledge
> >
> > just to share, I used DADT=C method, and it didn't depend on sampling after I tried with my model (which took quite a while to get results)
> >
> > -- I could do as Bill suggested setting up some small dataset and simple model to check first, then would share with the group ealier :-)
> >
> > ------------------------------------------------------------------------
> >
> > *From:* "[email protected]" <[email protected]>
> > *To:* [email protected]
> > *Sent:* Friday, March 20, 2009 9:42:59 AM
> > *Subject:* Fw: [NMusers] calculation of AUC
> >
> > I second Bill's suggestion to work this out on your own for your specific problem. This forum can help you with general questions and overall approaches, but very specific queries like this are for you and your colleagues to hash out.
> >
> > *Error! Filename not specified.*
> >
> > ----- Forwarded by Michael J Fossler/PharmRD/GSK on 03/20/2009 09:40 AM -----
> >
> > *"Bill Bachman" <[email protected]>*
> > Sent by: [email protected]
> >
> > 20-Mar-2009 09:17
> >
> > To
> >
> > "'Martin Bergstrand'" < [email protected] >, "'Ethan Wu'" < [email protected] >, [email protected]
> >
> > cc
> >
> > Subject
> >
> > RE: [NMusers] calculation of AUC
> >
> > The easiest answer is to work it out. Do some simulations (without variability) with multiple subjects with identical PK parameters BUT different sampling times. Tabulate your AUCs and compare the results for different sampling times!
> >
> > ------------------------------------------------------------------------
> >
> > *From:* [email protected] [ mailto: [email protected] ] *On Behalf Of *Martin Bergstrand*
> >
> > Sent:* Friday, March 20, 2009 8:45 AM*
> > To:* 'Ethan Wu'; [email protected]*
> > Subject:* RE: [NMusers] calculation of AUC
> >
> > Dear Ethan, You need to provide more information on how you plan to calculate AUC otherwise the question can’t be answered. It is of course possible to calculate the AUC without any influence of the sampling frequency. You should be able to find examples of how to do this in the NMusers archive. See for example the answer from Mats Karlsson in this thread ( http://nonmem..org/nonmem/nm/98apr032002.html < http://nonmem.org/nonmem/nm/98apr032002.html >). Kind regards, Martin Bergstrand, MSc, PhD student
> >
> > -----------------------------------------------
> > Department of Pharmaceutical Biosciences,
> > Uppsala University
> > -----------------------------------------------
> > P.O. Box 591
> > SE-751 24 Uppsala
> > Sweden
> > -----------------------------------------------
> > [email protected] <mailto:[email protected]>
> > -----------------------------------------------
> > Work: +46 18 471 4639
> > Mobile: +46 709 994 396
> > Fax: +46 18 471 4003
> >
> > *From:* [email protected] [ mailto: [email protected] ] *On Behalf Of *Ethan Wu*
> >
> > Sent:* den 20 mars 2009 13:05*
> > To:* [email protected]*
> > Subject:* [NMusers] calculation of AUC
> >
> > Hi all, to calculate AUC of one of the compartments using ADVAN6, if it is a fixed time interval, will the AUC be influenced by the frequncy of sampling of the dataset within this interval or not?
> >
> > thanks
> >
> > ------------------------------------------------------------------------
> >
> > No viruses found in this incoming message
> > Scanned by *iolo AntiVirus 1.5.6.4*_
> > _ http://www.iolo.com http://www.iolo.com/iav/iavpop3
--
Nick Holford, Dept Pharmacology & Clinical Pharmacology
University of Auckland, 85 Park Rd, Private Bag 92019, Auckland, New Zealand
[email protected] tel:+64(9)923-6730 fax:+64(9)373-7090
http://www.fmhs.auckland.ac.nz/sms/pharmacology/holford
Nick,
See comments below.
Mats
Mats Karlsson, PhD
Professor of Pharmacometrics
Dept of Pharmaceutical Biosciences
Uppsala University
Box 591
751 24 Uppsala Sweden
phone: +46 18 4714105
fax: +46 18 471 4003
Quoted reply history
-----Original Message-----
From: [email protected] [mailto:[email protected]] On
Behalf Of Nick Holford
Sent: Tuesday, March 24, 2009 8:07 PM
To: nmusers
Subject: Re: [NMusers] calculation of AUC
Mats,
Thanks for trying to explain things further but I am still confused. I
agree for the moment we can forget about shrinkage and about computing
the central tendency over a group of subjects.
Lets just fit one individual with a model and estimate clearance then
calculate AUC from Dose/CL. If we take the same concentration
observations and compute an AUC using a trapezoidal rule then I still
dont follow your example.
M> AUCs from a model are usually calculated either to drive PD or to compare
with NCA AUCs of observed data, as an internal validation. I was making a point
regarding the second use of model based AUCs. Of course there are many
situations where AUC is not dose/CL, whenever AUC is calculated by trapezoidal
rule is one of them.
If you want to compare like with like - model-based trapezoidal rule AUCs with
real data trapezoidal rule AUCs - you should also take into the error
generation structure. If you get data that have reported negative concentration
(as you discuss below) it is appropriate to use a simulation that mimics that.
I never see that type of data and try to mimic the error generation process of
more common structure. Naturally you should treat your simulated data just as
the real data.
You say:
"The exponentiation of (LOG(F)+EPS(1)) will not give the expected mean of F,
but something higher. [this is what you can calculate model-simulated NCA AUCs
from]"
but I dont understand what you mean by "this is what you calculate
model-simulate NCA AUCs from".
I am not thinking of calculating NCA AUCs from simulated concentrations.
I expect to use real measured concentrations.
Simulating concentrations which force all concentrations to be
non-negative is a biased simulation of reality. If there is any
possibility of an additive error then there is a possibility of a
negative measured concentration. Real assays can have additive errors so
real assays must be capable of measuring values that appear to be
negative. Note the difference between the true concentration which must
be non-negative and the measured concentration, i.e. the truth plus
error, which can be negative if the error is additive.
Nick
Mats Karlsson wrote:
> Dear Nick,
>
> I did not discuss shrinkage because it didn't concern the point I was trying
> (and maybe failing) to make. [However, I don't think that if one wants to
> compare with NCA AUCs, data are likely to be rich with reasonably small
> shrinkage]
>
> I used proportional residual error as an example. Doesn't really matter which
> residual error you use - going from the normality assumption on the log scale
> to normal scale would always make the mean of a simulated observation higher
> than the mean. Mean(exp(epsilon)) is going to be higher than 1 regardless of
> residual error model.
>
> The point I'm trying to make is not how you calculate the central tendency of
> several AUCs, it concerns the calculation of individual AUCs.
>
> The problem I point out is relevant when you compare NCA AUCs from observed
> data with NCA AUCs from model predictions, regardless if you use linear or
> log-linear trapezoidal rules. Observed NCA AUCs are expected to be higher
> than NCA AUCs from model-predicted (but not higher than model simulated) AUCs
> calculated by NCA (from the same sampling schedule).
> For a model:
> Y=LOG(F)+EPS(1)
> The exponentiation of LOG(F) will give the expected mean of F [from which
> model-predicted NCA AUC will be calculated]
> The exponentiation of (LOG(F)+EPS(1)) will not give the expected mean of F,
> but something higher. [this is what you can calculate model-simulated NCA
> AUCs from]
>
> Thus model-predicted and model-simulated NCA AUCs will be systematically
> different if they are calculated in this way. I expect that if the model is
> correct, the observed NCA AUCs will be more similar to the simulated NCA
> AUCs.
>
> Hope this makes it clearer.
>
> Best regards,
> Mats
>
>
> Mats Karlsson, PhD
> Professor of Pharmacometrics
> Dept of Pharmaceutical Biosciences
> Uppsala University
> Box 591
> 751 24 Uppsala Sweden
> phone: +46 18 4714105
> fax: +46 18 471 4003
>
>
> -----Original Message-----
> From: [email protected] [mailto:[email protected]] On
> Behalf Of Nick Holford
> Sent: Sunday, March 22, 2009 7:09 AM
> To: nmusers
> Subject: Re: [NMusers] calculation of AUC
>
> Mats,
>
> This is an interesting idea but it seems to be more complicated than
> just a consideration of the residual variability (RV%) when using log
> transformation with transform both sides (TBS) estimation.
>
> First of all you appear to assume that the RV% is only a proportional
> residual error but if could also include an additive component when
> using TBS so that there is not a single RV% that would describe a
> particular situation because it would change with concentration.
>
> A model based estimate of AUC would typically be based on an empirical
> Bayes estimate (EBE) of CL. This estimate is of course a shrinkage
> estimate which will typically be biased towards the population CL but I
> have realized that there is also EBE bias from the choice of
> transformation used in parameter estimation. Thus I would not expect the
> model based estimate to be additionally biased because of using EBEs
> with TBS. This is probably something you have thought about so please
> inform me.
>
> Turning to the NCA method - I dont know if a bias is expected from the
> NCA calculated AUC but I would naively assume that the trapezoidal part
> would not be biased. I am ready to learn if there is a bias expected
> with trapezoidal NCA. I expect this has been investigated and reported
> but I am not familiar with it. The extrapolated portion typically relies
> on a log linear transformation to estimate the elimination rate constant
> which so in this respect the log transformed model based and NCA based
> methods would seem to be similar.
>
> Another source of difference between model and NCA based AUCs might
> arise from the use of different statistics to describe the central
> tendency of the indidual estimates. NCA estimates could be based on the
> arithmetic mean of the individual AUC sor on the geometric mean (most
> commonly used for bioequivalence analysis). The model based estimates
> based on the arithmetic mean of the EBE predicted AUCs would be biased
> towards the geometric mean because the population value would typically
> be estimated with an exponential ETA.
>
> If you have the time would you expand on the details of your assertion
> so that I and others can understand the basis more clearly? It seems to
> me that comparison of model based AUCs with NCA based AUCs is more
> complicated than just a consideration of the typical value of the
> residual error.
>
> Nick
>
>
> Mats Karlsson wrote:
>
>> Dear Ethan,
>>
>>
>>
>> Just a caution when comparing model-based AUCs with NCA calculated
>> AUCs. If you have done your modeling using log-transformation of
>> observations and model predictions and then compared AUCs on the
>> linear scale, you should not expect a perfect agreement between the
>> two. The reason is that the mean of an exponentiated distribution of
>> epsilons is not the same as the median, but higher. Thus, the AUCs of
>> model-predicted individual profiles will be expected to be lower than
>> either simulated or observed. The magnitude of the difference will
>> depend on the residual error magnitude and will typically be:
>>
>>
>>
>> %RV expected AUC difference
>>
>> 10 0.50%
>>
>> 20 2%
>>
>> 30 5%
>>
>> 40 9%
>>
>> 50 14%
>>
>> 70 29%
>>
>>
>>
>> Best regards,
>>
>> Mats
>>
>>
>>
>> Mats Karlsson, PhD
>>
>> Professor of Pharmacometrics
>>
>> Dept of Pharmaceutical Biosciences
>>
>> Uppsala University
>>
>> Box 591
>>
>> 751 24 Uppsala Sweden
>>
>> phone: +46 18 4714105
>>
>> fax: +46 18 471 4003
>>
>>
>>
>> *From:* [email protected]
>> [mailto:[email protected]] *On Behalf Of *Ethan Wu
>> *Sent:* Friday, March 20, 2009 6:52 PM
>> *To:* [email protected]; [email protected]
>> *Subject:* Re: [NMusers] calculation of AUC
>>
>>
>>
>> sorry for being lazy this morning and wish relying on others knowledge
>>
>> just to share, I used DADT=C method, and it didn't depend on sampling
>> after I tried with my model (which took quite a while to get results)
>>
>> -- I could do as Bill suggested setting up some small dataset and
>> simple model to check first, then would share with the group ealier :-)
>>
>>
>>
>>
>>
>>
>> ------------------------------------------------------------------------
>>
>> *From:* "[email protected]" <[email protected]>
>> *To:* [email protected]
>> *Sent:* Friday, March 20, 2009 9:42:59 AM
>> *Subject:* Fw: [NMusers] calculation of AUC
>>
>>
>> I second Bill's suggestion to work this out on your own for your
>> specific problem. This forum can help you with general questions and
>> overall approaches, but very specific queries like this are for you
>> and your colleagues to hash out.
>>
>> *Error! Filename not specified.*
>> ----- Forwarded by Michael J Fossler/PharmRD/GSK on 03/20/2009 09:40
>> AM -----
>>
>> *"Bill Bachman" <[email protected]>*
>> Sent by: [email protected]
>>
>> 20-Mar-2009 09:17
>>
>>
>>
>>
>>
>> To
>>
>>
>>
>> "'Martin Bergstrand'" <[email protected]>, "'Ethan Wu'"
>> <[email protected]>, [email protected]
>>
>> cc
>>
>>
>>
>> Subject
>>
>>
>>
>> RE: [NMusers] calculation of AUC
>>
>>
>>
>>
>>
>>
>>
>>
>>
>> The easiest answer is to work it out. Do some simulations (without
>> variability) with multiple subjects with identical PK parameters BUT
>> different sampling times. Tabulate your AUCs and compare the results
>> for different sampling times!
>>
>>
>>
>>
>> ------------------------------------------------------------------------
>>
>>
>> *From:* [email protected]
>> [mailto:[email protected]] *On Behalf Of *Martin Bergstrand*
>> Sent:* Friday, March 20, 2009 8:45 AM*
>> To:* 'Ethan Wu'; [email protected]*
>> Subject:* RE: [NMusers] calculation of AUC
>>
>> Dear Ethan,
>>
>> You need to provide more information on how you plan to calculate AUC
>> otherwise the question can’t be answered. It is of course possible to
>> calculate the AUC without any influence of the sampling frequency. You
>> should be able to find examples of how to do this in the NMusers
>> archive. See for example the answer from Mats Karlsson in this thread
>> ( http://nonmem..org/nonmem/nm/98apr032002.html
>> http://nonmem.org/nonmem/nm/98apr032002.html).
>>
>> Kind regards,
>>
>> Martin Bergstrand, MSc, PhD student
>> -----------------------------------------------
>> Department of Pharmaceutical Biosciences,
>> Uppsala University
>> -----------------------------------------------
>> P.O. Box 591
>> SE-751 24 Uppsala
>> Sweden
>> -----------------------------------------------
>> [email protected] <mailto:[email protected]>
>> -----------------------------------------------
>> Work: +46 18 471 4639
>> Mobile: +46 709 994 396
>> Fax: +46 18 471 4003
>>
>>
>> *From:* [email protected]
>> [mailto:[email protected]] *On Behalf Of *Ethan Wu*
>> Sent:* den 20 mars 2009 13:05*
>> To:* [email protected]*
>> Subject:* [NMusers] calculation of AUC
>>
>> Hi all, to calculate AUC of one of the compartments using ADVAN6, if
>> it is a fixed time interval, will the AUC be influenced by the
>> frequncy of sampling of the dataset within this interval or not?
>> thanks
>>
>>
>> ------------------------------------------------------------------------
>>
>> No viruses found in this incoming message
>> Scanned by *iolo AntiVirus 1.5.6.4*_
>> _ http://www.iolo.com http://www.iolo.com/iav/iavpop3
>>
>>
>>
>>
>
>
--
Nick Holford, Dept Pharmacology & Clinical Pharmacology
University of Auckland, 85 Park Rd, Private Bag 92019, Auckland, New Zealand
[email protected] tel:+64(9)923-6730 fax:+64(9)373-7090
http://www.fmhs.auckland.ac.nz/sms/pharmacology/holford
I think Mats' description about NCA based AUC can be simplified to the
following(imagine only 2 time points):
Given two log-normally distributed random variable,
C1~log-N(log(F1),sigma**2) and C2~log-N(log(F2),sigma**2), what is the
relationship between C1+C2 (model simulated) and F1+F2(model predicted)?
Mats is saying average (mean) of C1+C2 is systematically greater than
F1+F2 (but a specific C1+C2 can be either less or greater than F1+F2).
This can be easily proved mathematically.
The distribution of the sum of two log-normally distributed random
variables is approximately another log-normal distribution(Fenton L).
Say Y+C2, then Y's distribution can be approximately by
log-N(log(median_Y),sigmasum**2), where
median_Y=(F1+F2)*exp(sigma**2/2-sigmasum**2/2). And
mean_Y=(F1+F2)*exp(sigma**2/2). Since exp(sigma**2/2) is always greater
than 1, mean_Y will be greater than F1+F2. I believe Mats' table is
based on simulation. The exact ratio (difference) is exp(sigma**2/2).
Notice F1 and F2 are the medians. Therefore I believe a more reasonable
statistic to be compared with F1+F2 should be median_Y. Then the ratio
will be exp(sigma**2/2-sigmasum**2/2), which will be much closer to 1
but still greater than 1 (sigmasum**2 can be proved to be less than
sigma**2). If there is only 1 time point (C1), median_Y will be equal
to F1 while mean_Y will still be greater than F1 by exp(sigma**2/2).
Fenton L., The Sum of Log-Normal Probability Distributions in Scatter
Transmission Systems, IRE Trans. Commun. Syst., vol. CS-8, pp. 57-67
Yaning Wang, Ph.D.
Team Leader, Pharmacometrics
Office of Clinical Pharmacology
Office of Translational Science
Center for Drug Evaluation and Research
U.S. Food and Drug Administration
Phone: 301-796-1624
Email: yaning.wang
"The contents of this message are mine personally and do not necessarily
reflect any position of the Government or the Food and Drug
Administration."
Quoted reply history
-----Original Message-----
From: owner-nmusers
On Behalf Of Mats Karlsson
Sent: Wednesday, March 25, 2009 5:16 PM
To: 'Nick Holford'; 'nmusers'
Subject: RE: [NMusers] calculation of AUC
Nick,
See comments below.
Mats
Mats Karlsson, PhD
Professor of Pharmacometrics
Dept of Pharmaceutical Biosciences
Uppsala University
Box 591
751 24 Uppsala Sweden
phone: +46 18 4714105
fax: +46 18 471 4003
-----Original Message-----
From: owner-nmusers
On Behalf Of Nick Holford
Sent: Tuesday, March 24, 2009 8:07 PM
To: nmusers
Subject: Re: [NMusers] calculation of AUC
Mats,
Thanks for trying to explain things further but I am still confused. I
agree for the moment we can forget about shrinkage and about computing
the central tendency over a group of subjects.
Lets just fit one individual with a model and estimate clearance then
calculate AUC from Dose/CL. If we take the same concentration
observations and compute an AUC using a trapezoidal rule then I still
dont follow your example.
M> AUCs from a model are usually calculated either to drive PD or to
compare with NCA AUCs of observed data, as an internal validation. I was
making a point regarding the second use of model based AUCs. Of course
there are many situations where AUC is not dose/CL, whenever AUC is
calculated by trapezoidal rule is one of them.
If you want to compare like with like - model-based trapezoidal rule
AUCs with real data trapezoidal rule AUCs - you should also take into
the error generation structure. If you get data that have reported
negative concentration (as you discuss below) it is appropriate to use a
simulation that mimics that. I never see that type of data and try to
mimic the error generation process of more common structure. Naturally
you should treat your simulated data just as the real data.
You say:
"The exponentiation of (LOG(F)+EPS(1)) will not give the expected mean
of F, but something higher. [this is what you can calculate
model-simulated NCA AUCs from]"
but I dont understand what you mean by "this is what you calculate
model-simulate NCA AUCs from".
I am not thinking of calculating NCA AUCs from simulated concentrations.
I expect to use real measured concentrations.
Simulating concentrations which force all concentrations to be
non-negative is a biased simulation of reality. If there is any
possibility of an additive error then there is a possibility of a
negative measured concentration. Real assays can have additive errors so
real assays must be capable of measuring values that appear to be
negative. Note the difference between the true concentration which must
be non-negative and the measured concentration, i.e. the truth plus
error, which can be negative if the error is additive.
Nick
Mats Karlsson wrote:
> Dear Nick,
>
> I did not discuss shrinkage because it didn't concern the point I was
trying (and maybe failing) to make. [However, I don't think that if one
wants to compare with NCA AUCs, data are likely to be rich with
reasonably small shrinkage]
>
> I used proportional residual error as an example. Doesn't really
matter which residual error you use - going from the normality
assumption on the log scale to normal scale would always make the mean
of a simulated observation higher than the mean. Mean(exp(epsilon)) is
going to be higher than 1 regardless of residual error model.
>
> The point I'm trying to make is not how you calculate the central
tendency of several AUCs, it concerns the calculation of individual
AUCs.
>
> The problem I point out is relevant when you compare NCA AUCs from
observed data with NCA AUCs from model predictions, regardless if you
use linear or log-linear trapezoidal rules. Observed NCA AUCs are
expected to be higher than NCA AUCs from model-predicted (but not higher
than model simulated) AUCs calculated by NCA (from the same sampling
schedule).
> For a model:
> Y=LOG(F)+EPS(1)
> The exponentiation of LOG(F) will give the expected mean of F [from
which model-predicted NCA AUC will be calculated]
> The exponentiation of (LOG(F)+EPS(1)) will not give the expected mean
of F, but something higher. [this is what you can calculate
model-simulated NCA AUCs from]
>
> Thus model-predicted and model-simulated NCA AUCs will be
systematically different if they are calculated in this way. I expect
that if the model is correct, the observed NCA AUCs will be more similar
to the simulated NCA AUCs.
>
> Hope this makes it clearer.
>
> Best regards,
> Mats
>
>
> Mats Karlsson, PhD
> Professor of Pharmacometrics
> Dept of Pharmaceutical Biosciences
> Uppsala University
> Box 591
> 751 24 Uppsala Sweden
> phone: +46 18 4714105
> fax: +46 18 471 4003
>
>
> -----Original Message-----
> From: owner-nmusers
[mailto:owner-nmusers
> Sent: Sunday, March 22, 2009 7:09 AM
> To: nmusers
> Subject: Re: [NMusers] calculation of AUC
>
> Mats,
>
> This is an interesting idea but it seems to be more complicated than
> just a consideration of the residual variability (RV%) when using log
> transformation with transform both sides (TBS) estimation.
>
> First of all you appear to assume that the RV% is only a proportional
> residual error but if could also include an additive component when
> using TBS so that there is not a single RV% that would describe a
> particular situation because it would change with concentration.
>
> A model based estimate of AUC would typically be based on an empirical
> Bayes estimate (EBE) of CL. This estimate is of course a shrinkage
> estimate which will typically be biased towards the population CL but
I
> have realized that there is also EBE bias from the choice of
> transformation used in parameter estimation. Thus I would not expect
the
> model based estimate to be additionally biased because of using EBEs
> with TBS. This is probably something you have thought about so please
> inform me.
>
> Turning to the NCA method - I dont know if a bias is expected from the
> NCA calculated AUC but I would naively assume that the trapezoidal
part
> would not be biased. I am ready to learn if there is a bias expected
> with trapezoidal NCA. I expect this has been investigated and reported
> but I am not familiar with it. The extrapolated portion typically
relies
> on a log linear transformation to estimate the elimination rate
constant
> which so in this respect the log transformed model based and NCA based
> methods would seem to be similar.
>
> Another source of difference between model and NCA based AUCs might
> arise from the use of different statistics to describe the central
> tendency of the indidual estimates. NCA estimates could be based on
the
> arithmetic mean of the individual AUC sor on the geometric mean (most
> commonly used for bioequivalence analysis). The model based estimates
> based on the arithmetic mean of the EBE predicted AUCs would be biased
> towards the geometric mean because the population value would
typically
> be estimated with an exponential ETA.
>
> If you have the time would you expand on the details of your assertion
> so that I and others can understand the basis more clearly? It seems
to
> me that comparison of model based AUCs with NCA based AUCs is more
> complicated than just a consideration of the typical value of the
> residual error.
>
> Nick
>
>
> Mats Karlsson wrote:
>
>> Dear Ethan,
>>
>>
>>
>> Just a caution when comparing model-based AUCs with NCA calculated
>> AUCs. If you have done your modeling using log-transformation of
>> observations and model predictions and then compared AUCs on the
>> linear scale, you should not expect a perfect agreement between the
>> two. The reason is that the mean of an exponentiated distribution of
>> epsilons is not the same as the median, but higher. Thus, the AUCs of
>> model-predicted individual profiles will be expected to be lower than
>> either simulated or observed. The magnitude of the difference will
>> depend on the residual error magnitude and will typically be:
>>
>>
>>
>> %RV expected AUC difference
>>
>> 10 0.50%
>>
>> 20 2%
>>
>> 30 5%
>>
>> 40 9%
>>
>> 50 14%
>>
>> 70 29%
>>
>>
>>
>> Best regards,
>>
>> Mats
>>
>>
>>
>> Mats Karlsson, PhD
>>
>> Professor of Pharmacometrics
>>
>> Dept of Pharmaceutical Biosciences
>>
>> Uppsala University
>>
>> Box 591
>>
>> 751 24 Uppsala Sweden
>>
>> phone: +46 18 4714105
>>
>> fax: +46 18 471 4003
>>
>>
>>
>> *From:* owner-nmusers
>> [mailto:owner-nmusers
>> *Sent:* Friday, March 20, 2009 6:52 PM
>> *To:* Michael.J.Fossler
>> *Subject:* Re: [NMusers] calculation of AUC
>>
>>
>>
>> sorry for being lazy this morning and wish relying on others
knowledge
>>
>> just to share, I used DADT=C method, and it didn't depend on
sampling
>> after I tried with my model (which took quite a while to get results)
>>
>> -- I could do as Bill suggested setting up some small dataset and
>> simple model to check first, then would share with the group ealier
:-)
>>
>>
>>
>>
>>
>>
>>
------------------------------------------------------------------------
>>
>> *From:* "Michael.J.Fossler
>> *To:* nmusers
>> *Sent:* Friday, March 20, 2009 9:42:59 AM
>> *Subject:* Fw: [NMusers] calculation of AUC
>>
>>
>> I second Bill's suggestion to work this out on your own for your
>> specific problem. This forum can help you with general questions and
>> overall approaches, but very specific queries like this are for you
>> and your colleagues to hash out.
>>
>> *Error! Filename not specified.*
>> ----- Forwarded by Michael J Fossler/PharmRD/GSK on 03/20/2009 09:40
>> AM -----
>>
>> *"Bill Bachman" <bachmanw
>> Sent by: owner-nmusers
>>
>> 20-Mar-2009 09:17
>>
>>
>>
>>
>>
>> To
>>
>>
>>
>> "'Martin Bergstrand'" <martin.bergstrand
>> <ethan.wu75
>>
>> cc
>>
>>
>>
>> Subject
>>
>>
>>
>> RE: [NMusers] calculation of AUC
>>
>>
>>
>>
>>
>>
>>
>>
>>
>> The easiest answer is to work it out. Do some simulations (without
>> variability) with multiple subjects with identical PK parameters BUT
>> different sampling times. Tabulate your AUCs and compare the results
>> for different sampling times!
>>
>>
>>
>>
>>
------------------------------------------------------------------------
>>
>>
>> *From:* owner-nmusers
>> [mailto:owner-nmusers
Bergstrand*
>> Sent:* Friday, March 20, 2009 8:45 AM*
>> To:* 'Ethan Wu'; nmusers
>> Subject:* RE: [NMusers] calculation of AUC
>>
>> Dear Ethan,
>>
>> You need to provide more information on how you plan to calculate AUC
>> otherwise the question can't be answered. It is of course possible to
>> calculate the AUC without any influence of the sampling frequency.
You
>> should be able to find examples of how to do this in the NMusers
>> archive. See for example the answer from Mats Karlsson in this thread
>> ( http://nonmem..org/nonmem/nm/98apr032002.html
>> http://nonmem.org/nonmem/nm/98apr032002.html).
>>
>> Kind regards,
>>
>> Martin Bergstrand, MSc, PhD student
>> -----------------------------------------------
>> Department of Pharmaceutical Biosciences,
>> Uppsala University
>> -----------------------------------------------
>> P.O. Box 591
>> SE-751 24 Uppsala
>> Sweden
>> -----------------------------------------------
>> martin.bergstrand
<mailto:martin.bergstrand
>> -----------------------------------------------
>> Work: +46 18 471 4639
>> Mobile: +46 709 994 396
>> Fax: +46 18 471 4003
>>
>>
>> *From:* owner-nmusers
>> [mailto:owner-nmusers
>> Sent:* den 20 mars 2009 13:05*
>> To:* nmusers
>> Subject:* [NMusers] calculation of AUC
>>
>> Hi all, to calculate AUC of one of the compartments using ADVAN6, if
>> it is a fixed time interval, will the AUC be influenced by the
>> frequncy of sampling of the dataset within this interval or not?
>> thanks
>>
>>
>>
------------------------------------------------------------------------
>>
>> No viruses found in this incoming message
>> Scanned by *iolo AntiVirus 1.5.6.4*_
>> _ http://www.iolo.com http://www.iolo.com/iav/iavpop3
>>
>>
>>
>>
>
>
--
Nick Holford, Dept Pharmacology & Clinical Pharmacology
University of Auckland, 85 Park Rd, Private Bag 92019, Auckland, New
Zealand
n.holford
http://www.fmhs.auckland.ac.nz/sms/pharmacology/holford
I think Mats' description about NCA based AUC can be simplified to the
following(imagine only 2 time points):
Given two log-normally distributed random variable,
C1~log-N(log(F1),sigma**2) and C2~log-N(log(F2),sigma**2), what is the
relationship between C1+C2 (model simulated) and F1+F2(model predicted)?
Mats is saying average (mean) of C1+C2 is systematically greater than
F1+F2 (but a specific C1+C2 can be either less or greater than F1+F2).
This can be easily proved mathematically.
The distribution of the sum of two log-normally distributed random
variables is approximately another log-normal distribution(Fenton L).
Say Y=C1+C2, then Y's distribution can be approximately by
log-N(log(median_Y),sigmasum**2), where
median_Y=(F1+F2)*exp(sigma**2/2-sigmasum**2/2). And
mean_Y=(F1+F2)*exp(sigma**2/2). Since exp(sigma**2/2) is always greater
than 1, mean_Y will be greater than F1+F2. I believe Mats' table is
based on simulation. The exact ratio (difference) is exp(sigma**2/2).
Notice F1 and F2 are the medians. Therefore I believe a more reasonable
statistic to be compared with F1+F2 should be median_Y. Then the ratio
will be exp(sigma**2/2-sigmasum**2/2), which will be much closer to 1
but still greater than 1 (sigmasum**2 can be proved to be less than
sigma**2). If there is only 1 time point (C1), median_Y will be equal
to F1 while mean_Y will still be greater than F1 by exp(sigma**2/2).
Fenton L., The Sum of Log-Normal Probability Distributions in Scatter
Transmission Systems, IRE Trans. Commun. Syst., vol. CS-8, pp. 57-67
Yaning Wang, Ph.D.
Team Leader, Pharmacometrics
Office of Clinical Pharmacology
Office of Translational Science
Center for Drug Evaluation and Research
U.S. Food and Drug Administration
Phone: 301-796-1624
Email: [email protected]
"The contents of this message are mine personally and do not necessarily
reflect any position of the Government or the Food and Drug
Administration."
Quoted reply history
-----Original Message-----
From: [email protected] [mailto:[email protected]]
On Behalf Of Mats Karlsson
Sent: Wednesday, March 25, 2009 5:16 PM
To: 'Nick Holford'; 'nmusers'
Subject: RE: [NMusers] calculation of AUC
Nick,
See comments below.
Mats
Mats Karlsson, PhD
Professor of Pharmacometrics
Dept of Pharmaceutical Biosciences
Uppsala University
Box 591
751 24 Uppsala Sweden
phone: +46 18 4714105
fax: +46 18 471 4003
-----Original Message-----
From: [email protected] [mailto:[email protected]]
On Behalf Of Nick Holford
Sent: Tuesday, March 24, 2009 8:07 PM
To: nmusers
Subject: Re: [NMusers] calculation of AUC
Mats,
Thanks for trying to explain things further but I am still confused. I
agree for the moment we can forget about shrinkage and about computing
the central tendency over a group of subjects.
Lets just fit one individual with a model and estimate clearance then
calculate AUC from Dose/CL. If we take the same concentration
observations and compute an AUC using a trapezoidal rule then I still
dont follow your example.
M> AUCs from a model are usually calculated either to drive PD or to
compare with NCA AUCs of observed data, as an internal validation. I was
making a point regarding the second use of model based AUCs. Of course
there are many situations where AUC is not dose/CL, whenever AUC is
calculated by trapezoidal rule is one of them.
If you want to compare like with like - model-based trapezoidal rule
AUCs with real data trapezoidal rule AUCs - you should also take into
the error generation structure. If you get data that have reported
negative concentration (as you discuss below) it is appropriate to use a
simulation that mimics that. I never see that type of data and try to
mimic the error generation process of more common structure. Naturally
you should treat your simulated data just as the real data.
You say:
"The exponentiation of (LOG(F)+EPS(1)) will not give the expected mean
of F, but something higher. [this is what you can calculate
model-simulated NCA AUCs from]"
but I dont understand what you mean by "this is what you calculate
model-simulate NCA AUCs from".
I am not thinking of calculating NCA AUCs from simulated concentrations.
I expect to use real measured concentrations.
Simulating concentrations which force all concentrations to be
non-negative is a biased simulation of reality. If there is any
possibility of an additive error then there is a possibility of a
negative measured concentration. Real assays can have additive errors so
real assays must be capable of measuring values that appear to be
negative. Note the difference between the true concentration which must
be non-negative and the measured concentration, i.e. the truth plus
error, which can be negative if the error is additive.
Nick
Mats Karlsson wrote:
> Dear Nick,
>
> I did not discuss shrinkage because it didn't concern the point I was
trying (and maybe failing) to make. [However, I don't think that if one
wants to compare with NCA AUCs, data are likely to be rich with
reasonably small shrinkage]
>
> I used proportional residual error as an example. Doesn't really
matter which residual error you use - going from the normality
assumption on the log scale to normal scale would always make the mean
of a simulated observation higher than the mean. Mean(exp(epsilon)) is
going to be higher than 1 regardless of residual error model.
>
> The point I'm trying to make is not how you calculate the central
tendency of several AUCs, it concerns the calculation of individual
AUCs.
>
> The problem I point out is relevant when you compare NCA AUCs from
observed data with NCA AUCs from model predictions, regardless if you
use linear or log-linear trapezoidal rules. Observed NCA AUCs are
expected to be higher than NCA AUCs from model-predicted (but not higher
than model simulated) AUCs calculated by NCA (from the same sampling
schedule).
> For a model:
> Y=LOG(F)+EPS(1)
> The exponentiation of LOG(F) will give the expected mean of F [from
which model-predicted NCA AUC will be calculated]
> The exponentiation of (LOG(F)+EPS(1)) will not give the expected mean
of F, but something higher. [this is what you can calculate
model-simulated NCA AUCs from]
>
> Thus model-predicted and model-simulated NCA AUCs will be
systematically different if they are calculated in this way. I expect
that if the model is correct, the observed NCA AUCs will be more similar
to the simulated NCA AUCs.
>
> Hope this makes it clearer.
>
> Best regards,
> Mats
>
>
> Mats Karlsson, PhD
> Professor of Pharmacometrics
> Dept of Pharmaceutical Biosciences
> Uppsala University
> Box 591
> 751 24 Uppsala Sweden
> phone: +46 18 4714105
> fax: +46 18 471 4003
>
>
> -----Original Message-----
> From: [email protected]
[mailto:[email protected]] On Behalf Of Nick Holford
> Sent: Sunday, March 22, 2009 7:09 AM
> To: nmusers
> Subject: Re: [NMusers] calculation of AUC
>
> Mats,
>
> This is an interesting idea but it seems to be more complicated than
> just a consideration of the residual variability (RV%) when using log
> transformation with transform both sides (TBS) estimation.
>
> First of all you appear to assume that the RV% is only a proportional
> residual error but if could also include an additive component when
> using TBS so that there is not a single RV% that would describe a
> particular situation because it would change with concentration.
>
> A model based estimate of AUC would typically be based on an empirical
> Bayes estimate (EBE) of CL. This estimate is of course a shrinkage
> estimate which will typically be biased towards the population CL but
I
> have realized that there is also EBE bias from the choice of
> transformation used in parameter estimation. Thus I would not expect
the
> model based estimate to be additionally biased because of using EBEs
> with TBS. This is probably something you have thought about so please
> inform me.
>
> Turning to the NCA method - I dont know if a bias is expected from the
> NCA calculated AUC but I would naively assume that the trapezoidal
part
> would not be biased. I am ready to learn if there is a bias expected
> with trapezoidal NCA. I expect this has been investigated and reported
> but I am not familiar with it. The extrapolated portion typically
relies
> on a log linear transformation to estimate the elimination rate
constant
> which so in this respect the log transformed model based and NCA based
> methods would seem to be similar.
>
> Another source of difference between model and NCA based AUCs might
> arise from the use of different statistics to describe the central
> tendency of the indidual estimates. NCA estimates could be based on
the
> arithmetic mean of the individual AUC sor on the geometric mean (most
> commonly used for bioequivalence analysis). The model based estimates
> based on the arithmetic mean of the EBE predicted AUCs would be biased
> towards the geometric mean because the population value would
typically
> be estimated with an exponential ETA.
>
> If you have the time would you expand on the details of your assertion
> so that I and others can understand the basis more clearly? It seems
to
> me that comparison of model based AUCs with NCA based AUCs is more
> complicated than just a consideration of the typical value of the
> residual error.
>
> Nick
>
>
> Mats Karlsson wrote:
>
>> Dear Ethan,
>>
>>
>>
>> Just a caution when comparing model-based AUCs with NCA calculated
>> AUCs. If you have done your modeling using log-transformation of
>> observations and model predictions and then compared AUCs on the
>> linear scale, you should not expect a perfect agreement between the
>> two. The reason is that the mean of an exponentiated distribution of
>> epsilons is not the same as the median, but higher. Thus, the AUCs of
>> model-predicted individual profiles will be expected to be lower than
>> either simulated or observed. The magnitude of the difference will
>> depend on the residual error magnitude and will typically be:
>>
>>
>>
>> %RV expected AUC difference
>>
>> 10 0.50%
>>
>> 20 2%
>>
>> 30 5%
>>
>> 40 9%
>>
>> 50 14%
>>
>> 70 29%
>>
>>
>>
>> Best regards,
>>
>> Mats
>>
>>
>>
>> Mats Karlsson, PhD
>>
>> Professor of Pharmacometrics
>>
>> Dept of Pharmaceutical Biosciences
>>
>> Uppsala University
>>
>> Box 591
>>
>> 751 24 Uppsala Sweden
>>
>> phone: +46 18 4714105
>>
>> fax: +46 18 471 4003
>>
>>
>>
>> *From:* [email protected]
>> [mailto:[email protected]] *On Behalf Of *Ethan Wu
>> *Sent:* Friday, March 20, 2009 6:52 PM
>> *To:* [email protected]; [email protected]
>> *Subject:* Re: [NMusers] calculation of AUC
>>
>>
>>
>> sorry for being lazy this morning and wish relying on others
knowledge
>>
>> just to share, I used DADT=C method, and it didn't depend on sampling
>> after I tried with my model (which took quite a while to get results)
>>
>> -- I could do as Bill suggested setting up some small dataset and
>> simple model to check first, then would share with the group ealier
:-)
>>
>>
>>
>>
>>
>>
>>
------------------------------------------------------------------------
>>
>> *From:* "[email protected]" <[email protected]>
>> *To:* [email protected]
>> *Sent:* Friday, March 20, 2009 9:42:59 AM
>> *Subject:* Fw: [NMusers] calculation of AUC
>>
>>
>> I second Bill's suggestion to work this out on your own for your
>> specific problem. This forum can help you with general questions and
>> overall approaches, but very specific queries like this are for you
>> and your colleagues to hash out.
>>
>> *Error! Filename not specified.*
>> ----- Forwarded by Michael J Fossler/PharmRD/GSK on 03/20/2009 09:40
>> AM -----
>>
>> *"Bill Bachman" <[email protected]>*
>> Sent by: [email protected]
>>
>> 20-Mar-2009 09:17
>>
>>
>>
>>
>>
>> To
>>
>>
>>
>> "'Martin Bergstrand'" <[email protected]>, "'Ethan Wu'"
>> <[email protected]>, [email protected]
>>
>> cc
>>
>>
>>
>> Subject
>>
>>
>>
>> RE: [NMusers] calculation of AUC
>>
>>
>>
>>
>>
>>
>>
>>
>>
>> The easiest answer is to work it out. Do some simulations (without
>> variability) with multiple subjects with identical PK parameters BUT
>> different sampling times. Tabulate your AUCs and compare the results
>> for different sampling times!
>>
>>
>>
>>
>>
------------------------------------------------------------------------
>>
>>
>> *From:* [email protected]
>> [mailto:[email protected]] *On Behalf Of *Martin
Bergstrand*
>> Sent:* Friday, March 20, 2009 8:45 AM*
>> To:* 'Ethan Wu'; [email protected]*
>> Subject:* RE: [NMusers] calculation of AUC
>>
>> Dear Ethan,
>>
>> You need to provide more information on how you plan to calculate AUC
>> otherwise the question can't be answered. It is of course possible to
>> calculate the AUC without any influence of the sampling frequency.
You
>> should be able to find examples of how to do this in the NMusers
>> archive. See for example the answer from Mats Karlsson in this thread
>> ( http://nonmem..org/nonmem/nm/98apr032002.html
>> http://nonmem.org/nonmem/nm/98apr032002.html).
>>
>> Kind regards,
>>
>> Martin Bergstrand, MSc, PhD student
>> -----------------------------------------------
>> Department of Pharmaceutical Biosciences,
>> Uppsala University
>> -----------------------------------------------
>> P.O. Box 591
>> SE-751 24 Uppsala
>> Sweden
>> -----------------------------------------------
>> [email protected]
<mailto:[email protected]>
>> -----------------------------------------------
>> Work: +46 18 471 4639
>> Mobile: +46 709 994 396
>> Fax: +46 18 471 4003
>>
>>
>> *From:* [email protected]
>> [mailto:[email protected]] *On Behalf Of *Ethan Wu*
>> Sent:* den 20 mars 2009 13:05*
>> To:* [email protected]*
>> Subject:* [NMusers] calculation of AUC
>>
>> Hi all, to calculate AUC of one of the compartments using ADVAN6, if
>> it is a fixed time interval, will the AUC be influenced by the
>> frequncy of sampling of the dataset within this interval or not?
>> thanks
>>
>>
>>
------------------------------------------------------------------------
>>
>> No viruses found in this incoming message
>> Scanned by *iolo AntiVirus 1.5.6.4*_
>> _ http://www.iolo.com http://www.iolo.com/iav/iavpop3
>>
>>
>>
>>
>
>
--
Nick Holford, Dept Pharmacology & Clinical Pharmacology
University of Auckland, 85 Park Rd, Private Bag 92019, Auckland, New
Zealand
[email protected] tel:+64(9)923-6730 fax:+64(9)373-7090
http://www.fmhs.auckland.ac.nz/sms/pharmacology/holford