Hello -
I was curious if someone from the group could perhaps describe the basis
for deciding whether to use a block (variance and covariance) versus
diagonal (variance only) form of omega. Specifically, what tests if any
can be performed to decide between the two forms and are there certain
situations where one is preferred over the other as I often see only the
diagonal form used. Any help would be much appreciated -
Al Berg, PhD/PharmD
Clinical Pharmacology Fellow
Mayo Clinic - Rochester
[email protected]
Block versus diagonal omega
21 messages
13 people
Latest: Sep 03, 2010
Does anyone know how I get OFF this list?
Thanks,
Janet
Quoted reply history
-------- Original Message --------
Subject: [NMusers] Block versus diagonal omega
Date: Wed, 25 Aug 2010 14:20:01 -0500
From: Berg, Alexander K., Pharm.D., Ph.D. <[email protected]>
To: <[email protected]>
Hello -
I was curious if someone from the group could perhaps describe the basis
for deciding whether to use a block (variance and covariance) versus
diagonal (variance only) form of omega. Specifically, what tests if any
can be performed to decide between the two forms and are there certain
situations where one is preferred over the other as I often see only the
diagonal form used. Any help would be much appreciated -
Al Berg, PhD/PharmD
Clinical Pharmacology Fellow
Mayo Clinic - Rochester
[email protected]
Hi Al,
One basis is to treat on off-diagonal element as just any other
parameter, and use your normal methods to decide whether to include it
or not. You may however, depending on the objective of your model, also
use another basis. Simulation purposes may largely benefit from
off-diagonal elements as off-diagonal elements limit the parameter space
the etas may expand into. E.g. VPCs may offer you diagnostics in this
respect. Such considerations may let you decide on a different
trade-off.
The reason that diagonal elements are more frequently encountered is
probably that they are more difficult to estimate, with more frequent
covariance failures and the like. But they are also more difficult to
implement, as it is not always straightforward to detect where those
elements can be inserted e.g. under shrinkage. Thirdly, perhaps not all
modelers are aware of the possibilities they offer.
Best regards,
Jeroen
Modeling & Simulation Expert
Pharmacokinetics, Pharmacodynamics & Pharmacometrics (P3) - DMPK
MSD
PO Box 20 - AP1112
5340 BH Oss
The Netherlands
[email protected]
T: +31 (0)412 66 9320
M: +31 (0)6 46 101 283
F: +31 (0)412 66 2506
www.msd.com
Quoted reply history
________________________________
From: [email protected] [mailto:[email protected]]
On Behalf Of Berg, Alexander K., Pharm.D., Ph.D.
Sent: Wednesday, 25 August, 2010 21:20
To: [email protected]
Subject: [NMusers] Block versus diagonal omega
Hello -
I was curious if someone from the group could perhaps describe the basis
for deciding whether to use a block (variance and covariance) versus
diagonal (variance only) form of omega. Specifically, what tests if any
can be performed to decide between the two forms and are there certain
situations where one is preferred over the other as I often see only the
diagonal form used. Any help would be much appreciated -
Al Berg, PhD/PharmD
Clinical Pharmacology Fellow
Mayo Clinic - Rochester
[email protected]
This message and any attachments are solely for the intended recipient. If you
are not the intended recipient, disclosure, copying, use or distribution of the
information included in this message is prohibited --- Please immediately and
permanently delete.
the same way you got on the list, send a message to
[email protected]. ask to unsubscribe.
Quoted reply history
-----Original Message-----
From: [email protected] [mailto:[email protected]] On
Behalf Of Bioengineering Faculty Search
Sent: Wednesday, August 25, 2010 3:59 PM
To: [email protected]
Subject: Fwd: [NMusers] Block versus diagonal omega
Does anyone know how I get OFF this list?
Thanks,
Janet
-------- Original Message --------
Subject: [NMusers] Block versus diagonal omega
Date: Wed, 25 Aug 2010 14:20:01 -0500
From: Berg, Alexander K., Pharm.D., Ph.D. <[email protected]>
To: <[email protected]>
Hello -
I was curious if someone from the group could perhaps describe the basis
for deciding whether to use a block (variance and covariance) versus
diagonal (variance only) form of omega. Specifically, what tests if any
can be performed to decide between the two forms and are there certain
situations where one is preferred over the other as I often see only the
diagonal form used. Any help would be much appreciated -
Al Berg, PhD/PharmD
Clinical Pharmacology Fellow
Mayo Clinic - Rochester
[email protected]
I am not sure there is one single statistical test you can use like we
do with covariate selection (forward followed by backward deletion
method).
The easiest way to deal with this problem would be first to use a stable
method like importance sampling assisted by MAP estimation (IMPMAP in
NONMEM7) and getting the full variance covariance matrix and correlation
matrix. NONMEM7 will give you also like SADAPT the standard errors
associated with each correlation coefficient. A way to categorize these
correlation coefficients would be to look at each correlation mean +- 2
standard errors and see if it crosses the zero cutoff. If so, you would
assume this correlation not to be statistically significant. Once all
the not statistically significant correlations are deleted, you have
your new blocks to be considered (I guess you have sometimes to change
the order of your parameters to define this new block in NONMEM7) and
you refit your model with this new blocks. Of course, this is an
approximation but at least it allows you ranking the most important
correlations based on both their mean but also their corresponding
standard errors.
A pure diagonal variance covariance matrix will affect the outcome of
your subsequent simulations and usually would inflate the response
variability across the population as important correlations are may be
missing.
Serge Guzy; Ph.D
President, CEO; POP_PHARM; INC;
www.poppharm.com
[email protected]
510 684 87 40
Quoted reply history
From: [email protected] [mailto:[email protected]]
On Behalf Of Berg, Alexander K., Pharm.D., Ph.D.
Sent: Wednesday, August 25, 2010 12:20 PM
To: [email protected]
Subject: [NMusers] Block versus diagonal omega
Hello -
I was curious if someone from the group could perhaps describe the basis
for deciding whether to use a block (variance and covariance) versus
diagonal (variance only) form of omega. Specifically, what tests if any
can be performed to decide between the two forms and are there certain
situations where one is preferred over the other as I often see only the
diagonal form used. Any help would be much appreciated -
Al Berg, PhD/PharmD
Clinical Pharmacology Fellow
Mayo Clinic - Rochester
[email protected]
--
The information contained in this email message may
contain confidential or legally privileged information and is intended solely
for the use of the named recipient(s). No confidentiality or privilege is
waived or lost by any transmission error. If the reader of this message is
not the intended recipient, please immediately delete the e-mail and all
copies of it from your system, destroy any hard copies of it and notify the
sender either by telephone or return e-mail. Any direct or indirect use,
disclosure, distribution, printing, or copying of any part of this message is
prohibited. Any views expressed in this message are those of the individual
sender, except where the message states otherwise and the sender is
authorized to state them to be the views of XOMA.
Hi Al,
Serge's suggestion is available in practise,however when we are considering
to add one covariate such as body weight to the parameter-CL,e.g.,the number of
off-diagonal elements retained in the base model may be different from the one
in the covariate model .As I have noticed,one or above off-diagonal elements
could cross the zero cutoff again and should be excluded from the OMEGA block
structure.So it is hardly to keep the constructure of OMEGA block same during
the model improvment .
In my opinion,if all the diagonal elements fall in an acceptable
interval,such as the CV of parameter is within 50%,there is no need to insert
the off-diagonal element.The off-diagonal element which means covariance
between the diagonal paramete,represents the correlation between them.So
another way is to refer to the scatter plots between ETAs estimated by the
model with diagonal elements .Which off-diagonal element is included depends
on the correlation between two ETAs in the scaterr plots.
Most frequently,the diagonal elements are enough.Do not be worried about that.
By the way, when we discussed the off-diagonal issue,we should not forget the
basic purpose of model building-to make the model predictive performance to be
in accordance with the observed values as far as possible.
Jeroen,
Do you mean the off-diagonal elements instead of diagonal elements when you
mentioned in the second paragraph,because I would like to believe the the
off-digonal elements are more difficult to estimate
hongbo ye
from nanjing city.
2010-08-26
yhb5442387
发件人: "Serge Guzy" <[email protected]>
发送时间: 2010-08-26 04:46
主 题: RE: [NMusers] Block versus diagonal omega
收件人: "Berg, Alexander K., Pharm.D., Ph.D." <[email protected]>,
<[email protected]>
I am not sure there is one single statistical test you can use like we do with
covariate selection (forward followed by backward deletion method).
The easiest way to deal with this problem would be first to use a stable method
like importance sampling assisted by MAP estimation (IMPMAP in NONMEM7) and
getting the full variance covariance matrix and correlation matrix. NONMEM7
will give you also like SADAPT the standard errors associated with each
correlation coefficient. A way to categorize these correlation coefficients
would be to look at each correlation mean +- 2 standard errors and see if it
crosses the zero cutoff. If so, you would assume this correlation not to be
statistically significant. Once all the not statistically significant
correlations are deleted, you have your new blocks to be considered (I guess
you have sometimes to change the order of your parameters to define this new
block in NONMEM7) and you refit your model with this new blocks. Of course,
this is an approximation but at least it allows you ranking the most important
correlations based on both their mean but also their corresponding standard
errors.
A pure diagonal variance covariance matrix will affect the outcome of your
subsequent simulations and usually would inflate the response variability
across the population as important correlations are may be missing.
Serge Guzy; Ph.D
President, CEO; POP_PHARM; INC;
www.poppharm.com
[email protected]
510 684 87 40
Quoted reply history
From: [email protected] [mailto:[email protected]] On
Behalf Of Berg, Alexander K., Pharm.D., Ph.D.
Sent: Wednesday, August 25, 2010 12:20 PM
To: [email protected]
Subject: [NMusers] Block versus diagonal omega
Hello -
I was curious if someone from the group could perhaps describe the basis for
deciding whether to use a block (variance and covariance) versus diagonal
(variance only) form of omega. Specifically, what tests if any can be
performed to decide between the two forms and are there certain situations
where one is preferred over the other as I often see only the diagonal form
used. Any help would be much appreciated -
Al Berg, PhD/PharmD
Clinical Pharmacology Fellow
Mayo Clinic - Rochester
[email protected]
The information contained in this email message may contain confidential or
legally privileged information and is intended solely for the use of the named
recipient(s). No confidentiality or privilege is waived or lost by any
transmission error. If the reader of this message is not the intended
recipient, please immediately delete the e-mail and all copies of it from your
system, destroy any hard copies of it and notify the sender either by telephone
or return e-mail. Any direct or indirect use, disclosure, distribution,
printing, or copying of any part of this message is prohibited. Any views
expressed in this message are those of the individual sender, except where the
message states otherwise and the sender is authorized to state them to be the
views of XOMA.
Dear Hongbo,
I would rather advocate to include off-diagonal elements if possible. The
off-diagonals can trim down the magnitude of the inter-individual variability.
And as we often notice that our VPC bands tend to be (initially) rather too
wide than too narrow, that can be needed. It is certainly useful when one
desires to simulate with the inter-individual variability components.
One might want to be careful with basing decisions about off-diagonal elements
on posthoc ETAs as shrinkage may induce or mask correlation between the
emperical bayesian estimates.
Indeed, I ment to indicate that off-diagonal elements are more difficult to
estimate. Thank you!
Best regards,
Jeroen
Modeling & Simulation Expert
Pharmacokinetics, Pharmacodynamics & Pharmacometrics (P3) - DMPK
MSD
PO Box 20 - AP1112
5340 BH Oss
The Netherlands
[email protected]
T: +31 (0)412 66 9320
F: +31 (0)412 66 2506
www.msd.com
Quoted reply history
________________________________
From: [email protected] [mailto:[email protected]] On
Behalf Of yhb5442387
Sent: Thursday, 26 August, 2010 11:38
To: nmusers
Subject: RE: [NMusers] Block versus diagonal omega
Hi Al,
Serge's suggestion is available in practise,however when we are considering
to add one covariate such as body weight to the parameter-CL,e.g.,the number of
off-diagonal elements retained in the base model may be different from the one
in the covariate model .As I have noticed,one or above off-diagonal elements
could cross the zero cutoff again and should be excluded from the OMEGA block
structure.So it is hardly to keep the constructure of OMEGA block same during
the model improvment .
In my opinion,if all the diagonal elements fall in an acceptable
interval,such as the CV of parameter is within 50%,there is no need to insert
the off-diagonal element.The off-diagonal element which means covariance
between the diagonal paramete,represents the correlation between them.So
another way is to refer to the scatter plots between ETAs estimated by the
model with diagonal elements .Which off-diagonal element is included depends
on the correlation between two ETAs in the scaterr plots.
Most frequently,the diagonal elements are enough.Do not be worried about that.
By the way, when we discussed the off-diagonal issue,we should not forget the
basic purpose of model building-to make the model predictive performance to be
in accordance with the observed values as far as possible.
Jeroen,
Do you mean the off-diagonal elements instead of diagonal elements when you
mentioned in the second paragraph,because I would like to believe the the
off-digonal elements are more difficult to estimate
hongbo ye
from nanjing city.
2010-08-26
________________________________
yhb5442387
________________________________
发件人: "Serge Guzy" <[email protected]>
发送时间: 2010-08-26 04:46
主 题: RE: [NMusers] Block versus diagonal omega
收件人: "Berg, Alexander K., Pharm.D., Ph.D." <[email protected]>,
<[email protected]>
I am not sure there is one single statistical test you can use like we do with
covariate selection (forward followed by backward deletion method).
The easiest way to deal with this problem would be first to use a stable method
like importance sampling assisted by MAP estimation (IMPMAP in NONMEM7) and
getting the full variance covariance matrix and correlation matrix. NONMEM7
will give you also like SADAPT the standard errors associated with each
correlation coefficient. A way to categorize these correlation coefficients
would be to look at each correlation mean +- 2 standard errors and see if it
crosses the zero cutoff. If so, you would assume this correlation not to be
statistically significant. Once all the not statistically significant
correlations are deleted, you have your new blocks to be considered (I guess
you have sometimes to change the order of your parameters to define this new
block in NONMEM7) and you refit your model with this new blocks. Of course,
this is an approximation but at least it allows you ranking the most important
correlations based on both their mean but also their corresponding standard
errors.
A pure diagonal variance covariance matrix will affect the outcome of your
subsequent simulations and usually would inflate the response variability
across the population as important correlations are may be missing.
Serge Guzy; Ph.D
President, CEO; POP_PHARM; INC;
www.poppharm.com
[email protected]
510 684 87 40
From: [email protected] [mailto:[email protected]] On
Behalf Of Berg, Alexander K., Pharm.D., Ph.D.
Sent: Wednesday, August 25, 2010 12:20 PM
To: [email protected]
Subject: [NMusers] Block versus diagonal omega
Hello -
I was curious if someone from the group could perhaps describe the basis for
deciding whether to use a block (variance and covariance) versus diagonal
(variance only) form of omega. Specifically, what tests if any can be
performed to decide between the two forms and are there certain situations
where one is preferred over the other as I often see only the diagonal form
used. Any help would be much appreciated -
Al Berg, PhD/PharmD
Clinical Pharmacology Fellow
Mayo Clinic - Rochester
[email protected]
________________________________
The information contained in this email message may contain confidential or
legally privileged information and is intended solely for the use of the named
recipient(s). No confidentiality or privilege is waived or lost by any
transmission error. If the reader of this message is not the intended
recipient, please immediately delete the e-mail and all copies of it from your
system, destroy any hard copies of it and notify the sender either by telephone
or return e-mail. Any direct or indirect use, disclosure, distribution,
printing, or copying of any part of this message is prohibited. Any views
expressed in this message are those of the individual sender, except where the
message states otherwise and the sender is authorized to state them to be the
views of XOMA.
This message and any attachments are solely for the intended recipient. If you
are not the intended recipient, disclosure, copying, use or distribution of the
information included in this message is prohibited --- Please immediately and
permanently delete.
Title: Block versus diagonal omega
Jeroen, You're experience is a little different from mine. I've often been impressed that permitting correlation of inter individual variation allow the OMEGAs to become larger. My explanation was that, if Mr A (a 100 kg person) appears to have + ETA on volume, requiring him to have a expected value to ETA (i.e. off diagonal value of 0) on clearance is a constraint. Allowing that ETA to be associated with a value other than 0, in my experience, frequently results in an even larger OMEGA. But, I really have no criteria for including off diagonal omegas, except my prior that pretty much everything in biology is correlated, and enforcing a lack of correlation is a contraint I'd like to avoid. I agree with you that plots of post-hoc ETAs (ETA(1) vs ETA(2)) can be misleading. I find that posthoc plots of anything are frequently misleading, but I do them anyway. So, I typically try to include as many off diagonals as I can numerically support. And I very much agree that it is important to include as much inter individual variability as possible (variances and covariances) if the purpose is simulation. So, in the end, we have the same advise, I think, put them in if you can. I do find that including them can greatly reduce residual (intra individual) variance, but that commonly the VPC bands are wider (making NPC, NPDE and PPC easier to pass, a side benefit). Mark Sale MD Next Level Solutions, LLC www.NextLevelSolns.com 919-846-9185 A carbon-neutral company See our real time solar energy production at: http://enlighten.enphaseenergy.com/public/systems/aSDz2458
Quoted reply history
-------- Original Message --------
Subject: RE: [NMusers] Block versus diagonal omega
From: "Elassaiss - Schaap, J. \(Jeroen\)" < [email protected] >
Date: Thu, August 26, 2010 3:58 pm
To: "yhb5442387" < [email protected] >, "nmusers"
< [email protected] >
Dear Hongbo, I would rather advocate to include off-diagonal elements if possible. The off-diagonals can trim down the magnitude of the inter-individual variability. And as we often notice that our VPC bands tend to be (initially) rather too wide than too narrow, that can be needed. It is certainly useful when one desires to simulate with the inter-individual variability components. One might want to be careful with basing decisions about off-diagonal elements on posthoc ETAs as shrinkage may induce or mask correlation between the emperical bayesian estimates. Indeed, I ment to indicate that off-diagonal elements are more difficult to estimate. Thank you! Best regards, Jeroen Modeling & Simulation Expert Pharmacokinetics, Pharmacodynamics & Pharmacometrics (P3) - DMPK MSD PO Box 20 - AP1112 5340 BH Oss The Netherlands [email protected] T: +31 (0)412 66 9320 F: +31 (0)412 66 2506 www.msd.com From: [email protected] [ mailto: [email protected] ] On Behalf Of yhb5442387 Sent: Thursday, 26 August, 2010 11:38 To: nmusers Subject: RE: [NMusers] Block versus diagonal omega Hi Al, Serge's suggestion is available in practise,however when we are considering to add one covariate such as body weight to the parameter-CL,e.g.,the number of off-diagonal elements retained in the base model may be different from the one in the covariate model .As I have noticed,one or above off-diagonal elements could cross the zero cutoff again and should be excluded from the OMEGA block structure.So it is hardly to keep the constructure of OMEGA block same during the model improvment . In my opinion,if all the diagonal elements fall in an acceptable interval,such as the CV of parameter is within 50%,there is no need to insert the off-diagonal element.The off-diagonal element which means covariance between the diagonal paramete,represents the correlation between them.So another way is to refer to the scatter plots between ETAs estimated by the model with diagonal elements .Which off-diagonal element is included depends on the correlation between two ETAs in the scaterr plots. Most frequently,the diagonal elements are enough.Do not be worried about that. By the way, when we discussed the off-diagonal issue,we should not forget the basic purpose of model building-to make the model predictive performance to be in accordance with the observed values as far as possible. Jeroen, Do you mean the off-diagonal elements instead of diagonal elements when you mentioned in the second paragraph,because I would like to believe the the off-digonal elements are more difficult to estimate hongbo ye from nanjing city. 2010-08-26 yhb5442387 发件人: "Serge Guzy" < [email protected] > 发送时间: 2010-08-26 04:46 主 题: RE: [NMusers] Block versus diagonal omega 收件人: "Berg, Alexander K., Pharm.D., Ph.D." < [email protected] >, < [email protected] > I am not sure there is one single statistical test you can use like we do with covariate selection (forward followed by backward deletion method). The easiest way to deal with this problem would be first to use a stable method like importance sampling assisted by MAP estimation (IMPMAP in NONMEM7) and getting the full variance covariance matrix and correlation matrix. NONMEM7 will give you also like SADAPT the standard errors associated with each correlation coefficient. A way to categorize these correlation coefficients would be to look at each correlation mean +- 2 standard errors and see if it crosses the zero cutoff. If so, you would assume this correlation not to be statistically significant. Once all the not statistically significant correlations are deleted, you have your new blocks to be considered (I guess you have sometimes to change the order of your parameters to define this new block in NONMEM7) and you refit your model with this new blocks. Of course, this is an approximation but at least it allows you ranking the most important correlations based on both their mean but also their corresponding standard errors. A pure diagonal variance covariance matrix will affect the outcome of your subsequent simulations and usually would inflate the response variability across the population as important correlations are may be missing. Serge Guzy; Ph.D President, CEO; POP_PHARM; INC; www.poppharm.com [email protected] 510 684 87 40 From: [email protected] [ mailto: [email protected] ] On Behalf Of Berg, Alexander K., Pharm.D., Ph.D. Sent: Wednesday, August 25, 2010 12:20 PM To: [email protected] Subject: [NMusers] Block versus diagonal omega Hello - I was curious if someone from the group could perhaps describe the basis for deciding whether to use a block (variance and covariance) versus diagonal (variance only) form of omega. Specifically, what tests if any can be performed to decide between the two forms and are there certain situations where one is preferred over the other as I often see only the diagonal form used. Any help would be much appreciated - Al Berg, PhD/PharmD Clinical Pharmacology Fellow Mayo Clinic - Rochester [email protected] The information contained in this email message may contain confidential or legally privileged information and is intended solely for the use of the named recipient(s). No confidentiality or privilege is waived or lost by any transmission error. If the reader of this message is not the intended recipient, please immediately delete the e-mail and all copies of it from your system, destroy any hard copies of it and notify the sender either by telephone or return e-mail. Any direct or indirect use, disclosure, distribution, printing, or copying of any part of this message is prohibited. Any views expressed in this message are those of the individual sender, except where the message states otherwise and the sender is authorized to state them to be the views of XOMA. This message and any attachments are solely for the intended recipient. If you are not the intended recipient, disclosure, copying, use or distribution of the information included in this message is prohibited --- Please immediately and permanently delete.
Hi Jeroen,
If shrinkage induces correlations (which arent "true") in the posthoc ETAs then
the data isnt very informative for at least 1 of the parameters. If this
(misleading) correlation causes the researcher to test a model with
off-diagonal covariance, I would expect that they would not find a significant
drop in objective function, and therefore they would reject the correlation
from the model. So, in the end, no harm done (to the model). My thinking is
that if the data is not informative about the value of some parameter, then it
probably wont be informative about the relationship between that paramater with
some other parameter.
The concerns about how to handle shrinkage properly simply disappear if you
treat the off-diagonal elements like any other parameter, i.e. you require some
drop in objective function when you accept a parameter into the model.
Best regards,
Douglas Eleveld
________________________________
Quoted reply history
Van: [email protected] [mailto:[email protected]] Namens
Elassaiss - Schaap, J. (Jeroen)
Verzonden: August 26, 2010 9:58 PM
Aan: yhb5442387; nmusers
Onderwerp: RE: [NMusers] Block versus diagonal omega
Dear Hongbo,
I would rather advocate to include off-diagonal elements if possible. The
off-diagonals can trim down the magnitude of the inter-individual variability.
And as we often notice that our VPC bands tend to be (initially) rather too
wide than too narrow, that can be needed. It is certainly useful when one
desires to simulate with the inter-individual variability components.
One might want to be careful with basing decisions about off-diagonal elements
on posthoc ETAs as shrinkage may induce or mask correlation between the
emperical bayesian estimates.
Indeed, I ment to indicate that off-diagonal elements are more difficult to
estimate. Thank you!
Best regards,
Jeroen
Modeling & Simulation Expert
Pharmacokinetics, Pharmacodynamics & Pharmacometrics (P3) - DMPK
MSD
PO Box 20 - AP1112
5340 BH Oss
The Netherlands
[email protected]
T: +31 (0)412 66 9320
F: +31 (0)412 66 2506
www.msd.com
________________________________
From: [email protected] [mailto:[email protected]] On
Behalf Of yhb5442387
Sent: Thursday, 26 August, 2010 11:38
To: nmusers
Subject: RE: [NMusers] Block versus diagonal omega
Hi Al,
Serge's suggestion is available in practise,however when we are considering
to add one covariate such as body weight to the parameter-CL,e.g.,the number of
off-diagonal elements retained in the base model may be different from the one
in the covariate model .As I have noticed,one or above off-diagonal elements
could cross the zero cutoff again and should be excluded from the OMEGA block
structure.So it is hardly to keep the constructure of OMEGA block same during
the model improvment .
In my opinion,if all the diagonal elements fall in an acceptable
interval,such as the CV of parameter is within 50%,there is no need to insert
the off-diagonal element.The off-diagonal element which means covariance
between the diagonal paramete,represents the correlation between them.So
another way is to refer to the scatter plots between ETAs estimated by the
model with diagonal elements .Which off-diagonal element is included depends
on the correlation between two ETAs in the scaterr plots.
Most frequently,the diagonal elements are enough.Do not be worried about that.
By the way, when we discussed the off-diagonal issue,we should not forget the
basic purpose of model building-to make the model predictive performance to be
in accordance with the observed values as far as possible.
Jeroen,
Do you mean the off-diagonal elements instead of diagonal elements when you
mentioned in the second paragraph,because I would like to believe the the
off-digonal elements are more difficult to estimate
hongbo ye
from nanjing city.
2010-08-26
________________________________
yhb5442387
________________________________
发件人: "Serge Guzy" <[email protected]>
发送时间: 2010-08-26 04:46
主 题: RE: [NMusers] Block versus diagonal omega
收件人: "Berg, Alexander K., Pharm.D., Ph.D." <[email protected]>,
<[email protected]>
I am not sure there is one single statistical test you can use like we do with
covariate selection (forward followed by backward deletion method).
The easiest way to deal with this problem would be first to use a stable method
like importance sampling assisted by MAP estimation (IMPMAP in NONMEM7) and
getting the full variance covariance matrix and correlation matrix. NONMEM7
will give you also like SADAPT the standard errors associated with each
correlation coefficient. A way to categorize these correlation coefficients
would be to look at each correlation mean +- 2 standard errors and see if it
crosses the zero cutoff. If so, you would assume this correlation not to be
statistically significant. Once all the not statistically significant
correlations are deleted, you have your new blocks to be considered (I guess
you have sometimes to change the order of your parameters to define this new
block in NONMEM7) and you refit your model with this new blocks. Of course,
this is an approximation but at least it allows you ranking the most important
correlations based on both their mean but also their corresponding standard
errors.
A pure diagonal variance covariance matrix will affect the outcome of your
subsequent simulations and usually would inflate the response variability
across the population as important correlations are may be missing.
Serge Guzy; Ph.D
President, CEO; POP_PHARM; INC;
www.poppharm.com
[email protected]
510 684 87 40
From: [email protected] [mailto:[email protected]] On
Behalf Of Berg, Alexander K., Pharm.D., Ph.D.
Sent: Wednesday, August 25, 2010 12:20 PM
To: [email protected]
Subject: [NMusers] Block versus diagonal omega
Hello -
I was curious if someone from the group could perhaps describe the basis for
deciding whether to use a block (variance and covariance) versus diagonal
(variance only) form of omega. Specifically, what tests if any can be
performed to decide between the two forms and are there certain situations
where one is preferred over the other as I often see only the diagonal form
used. Any help would be much appreciated -
Al Berg, PhD/PharmD
Clinical Pharmacology Fellow
Mayo Clinic - Rochester
[email protected]
________________________________
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Title: Block versus diagonal omega
Douglas, But how large a drop? As I understand it, adding elements to OMEGA (diagonal or off diagonal) do not follow a chi-square distribtion, and therefore there is not any basis for determining how large a drop is significant. Mark Sale MD Next Level Solutions, LLC www.NextLevelSolns.com 919-846-9185 A carbon-neutral company See our real time solar energy production at: http://enlighten.enphaseenergy.com/public/systems/aSDz2458
Quoted reply history
-------- Original Message --------
Subject: RE: [NMusers] Block versus diagonal omega
From: "Eleveld, DJ" < [email protected] >
Date: Fri, August 27, 2010 4:52 am
To: "Elassaiss - Schaap, J. (Jeroen)" < [email protected] >,
"yhb5442387" < [email protected] >, "nmusers"
< [email protected] >
Hi Jeroen, If shrinkage induces correlations (which arent "true") in the posthoc ETAs then the data isnt very informative for at least 1 of the parameters. If this (misleading) correlation causes the researcher to test a model with off-diagonal covariance, I would expect that they would not find a significant drop in objective function, and therefore they would reject the correlation from the model. So, in the end, no harm done (to the model). My thinking is that if the data is not informative about the value of some parameter, then it probably wont be informative about the relationship between that paramater with some other parameter. The concerns about how to handle shrinkage properly simply disappear if you treat the off-diagonal elements like any other parameter, i.e. you require some drop in objective function when you accept a parameter into the model. Best regards, Douglas Eleveld Van: [email protected] [ mailto: [email protected] ] Namens Elassaiss - Schaap, J. (Jeroen) Verzonden: August 26, 2010 9:58 PM Aan: yhb5442387; nmusers Onderwerp: RE: [NMusers] Block versus diagonal omega Dear Hongbo, I would rather advocate to include off-diagonal elements if possible. The off-diagonals can trim down the magnitude of the inter-individual variability. And as we often notice that our VPC bands tend to be (initially) rather too wide than too narrow, that can be needed. It is certainly useful when one desires to simulate with the inter-individual variability components. One might want to be careful with basing decisions about off-diagonal elements on posthoc ETAs as shrinkage may induce or mask correlation between the emperical bayesian estimates. Indeed, I ment to indicate that off-diagonal elements are more difficult to estimate. Thank you! Best regards, Jeroen Modeling & Simulation Expert Pharmacokinetics, Pharmacodynamics & Pharmacometrics (P3) - DMPK MSD PO Box 20 - AP1112 5340 BH Oss The Netherlands [email protected] T: +31 (0)412 66 9320 F: +31 (0)412 66 2506 www.msd.com From: [email protected] [ mailto: [email protected] ] On Behalf Of yhb5442387 Sent: Thursday, 26 August, 2010 11:38 To: nmusers Subject: RE: [NMusers] Block versus diagonal omega Hi Al, Serge's suggestion is available in practise,however when we are considering to add one covariate such as body weight to the parameter-CL,e.g.,the number of off-diagonal elements retained in the base model may be different from the one in the covariate model .As I have noticed,one or above off-diagonal elements could cross the zero cutoff again and should be excluded from the OMEGA block structure.So it is hardly to keep the constructure of OMEGA block same during the model improvment . In my opinion,if all the diagonal elements fall in an acceptable interval,such as the CV of parameter is within 50%,there is no need to insert the off-diagonal element.The off-diagonal element which means covariance between the diagonal paramete,represents the correlation between them.So another way is to refer to the scatter plots between ETAs estimated by the model with diagonal elements .Which off-diagonal element is included depends on the correlation between two ETAs in the scaterr plots. Most frequently,the diagonal elements are enough.Do not be worried about that. By the way, when we discussed the off-diagonal issue,we should not forget the basic purpose of model building-to make the model predictive performance to be in accordance with the observed values as far as possible. Jeroen, Do you mean the off-diagonal elements instead of diagonal elements when you mentioned in the second paragraph,because I would like to believe the the off-digonal elements are more difficult to estimate hongbo ye from nanjing city. 2010-08-26 yhb5442387 发件人: "Serge Guzy" < [email protected] > 发送时间: 2010-08-26 04:46 主 题: RE: [NMusers] Block versus diagonal omega 收件人: "Berg, Alexander K., Pharm.D., Ph.D." < [email protected] >, < [email protected] > I am not sure there is one single statistical test you can use like we do with covariate selection (forward followed by backward deletion method). The easiest way to deal with this problem would be first to use a stable method like importance sampling assisted by MAP estimation (IMPMAP in NONMEM7) and getting the full variance covariance matrix and correlation matrix. NONMEM7 will give you also like SADAPT the standard errors associated with each correlation coefficient. A way to categorize these correlation coefficients would be to look at each correlation mean +- 2 standard errors and see if it crosses the zero cutoff. If so, you would assume this correlation not to be statistically significant. Once all the not statistically significant correlations are deleted, you have your new blocks to be considered (I guess you have sometimes to change the order of your parameters to define this new block in NONMEM7) and you refit your model with this new blocks. Of course, this is an approximation but at least it allows you ranking the most important correlations based on both their mean but also their corresponding standard errors. A pure diagonal variance covariance matrix will affect the outcome of your subsequent simulations and usually would inflate the response variability across the population as important correlations are may be missing. Serge Guzy; Ph.D President, CEO; POP_PHARM; INC; www.poppharm.com [email protected] 510 684 87 40 From: [email protected] [ mailto: [email protected] ] On Behalf Of Berg, Alexander K., Pharm.D., Ph.D. Sent: Wednesday, August 25, 2010 12:20 PM To: [email protected] Subject: [NMusers] Block versus diagonal omega Hello - I was curious if someone from the group could perhaps describe the basis for deciding whether to use a block (variance and covariance) versus diagonal (variance only) form of omega. Specifically, what tests if any can be performed to decide between the two forms and are there certain situations where one is preferred over the other as I often see only the diagonal form used. Any help would be much appreciated - Al Berg, PhD/PharmD Clinical Pharmacology Fellow Mayo Clinic - Rochester [email protected] The information contained in this email message may contain confidential or legally privileged information and is intended solely for the use of the named recipient(s). No confidentiality or privilege is waived or lost by any transmission error. If the reader of this message is not the intended recipient, please immediately delete the e-mail and all copies of it from your system, destroy any hard copies of it and notify the sender either by telephone or return e-mail. Any direct or indirect use, disclosure, distribution, printing, or copying of any part of this message is prohibited. Any views expressed in this message are those of the individual sender, except where the message states otherwise and the sender is authorized to state them to be the views of XOMA. This message and any attachments are solely for the intended recipient. If you are not the intended recipient, disclosure, copying, use or distribution of the information included in this message is prohibited --- Please immediately and permanently delete.
Mark,
Glad that we end up with the same advice ;-).
But even if the estimates of the diagonal elements increase a bit, it
does not mean that the total spread in the predictions increases. To
illustrate that I have written an R script that samples from a 2-by-2
matrix and simulates a bundle of emax-curves from it, attached at the
end of this mail. This clearly shows that the off-diagonal element
decreases the prediction space of the model. A 2-fold increase of the
total magnitude of variance does not even compensate for that around the
ec50 (although at the emax it does more or less). With a 10-fold
multiplier the band around the ec50 gets into the same order of
magnitude; the patterns that appear obviously are different from the
uncorrelated case.
I have never tried to summarize differences with an off-diagonal with a
diagnostic, but $OMEGA can be diagnosed similar to the covariance matrix
of estimation. The condition number seems an obvious choice although it
only focuses on the extremes .The larger the condition number the more
effect the off-diagonal elements have. The condition numbers of the
_normalized_ matrix in the examples below are .0263 and 1, respectively.
Best regards,
Jeroen
Modeling & Simulation Expert
Pharmacokinetics, Pharmacodynamics & Pharmacometrics (P3) - DMPK
MSD
PO Box 20 - AP1112
5340 BH Oss
The Netherlands
[email protected]
T: +31 (0)412 66 9320
F: +31 (0)412 66 2506
www.msd.com
R code for simulations:
library(MASS)
par(mfrow=c(2,2))
a<-matrix(c(2,1.2,1.2,.8),nrow=2)
b<-matrix(c(2,0,0,.8),nrow=2)
c<-matrix(c(2,1.2,1.2,.8)*2,nrow=2)
d<-matrix(c(2,1.2,1.2,.8)*10,nrow=2)
a.sample<-mvrnorm(50,c(10,10),a)
b.sample<-mvrnorm(50,c(10,10),b)
c.sample<-mvrnorm(50,c(10,10),c)
d.sample<-mvrnorm(50,c(10,10),d)
conc<- 10^((-25:25)/20+1)
emaxf<-function(p){
ec50<-p[1];emax<-p[2]
emax*conc/(ec50+conc)
}
correlated<-apply(a.sample,1,emaxf)
uncorrelated<-apply(b.sample,1,emaxf)
inflated<-apply(c.sample,1,emaxf)
more.inflated<-apply(d.sample,1,emaxf)
matplot(conc,correlated,log='x',type='l',ylim=c(0,12))
matplot(conc,uncorrelated,log='x',type='l',ylim=c(0,12))
matplot(conc,inflated,log='x',type='l',ylim=c(0,12))
matplot(conc,more.inflated,log='x',type='l',ylim=c(0,12))
[remaining stuff deleted to increase change of acceptance by list server
;-)]
This message and any attachments are solely for the intended recipient. If you
are not the intended recipient, disclosure, copying, use or distribution of the
information included in this message is prohibited --- Please immediately and
permanently delete.
From: Hu, Chuanpu [CNTUS]
Sent: Monday, August 30, 2010 8:46 AM
To: 'Mark Sale'
Cc: 'nmusers'
Subject: RE: [NMusers] Block versus diagonal omega
Mark,
Nice thought – the test can be conducted, but the devil is in the details. This
has to do with the intricacies of the role alternative hypothesis plays in
hypothesis testing:
For the original parameterization testing OMEGA, the hypothesis test is
H0: OMEGA=0, vs. H1: OMEGA>0
For the THETA parameterization testing OMEGA, the hypothesis test is
H0: THETA=0, vs. H1: THETA<>0
So without getting into the math, the intuitive argument is that the
alternative hypotheses in the 2 situations are different, therefore it is
logical that the testing criteria must change. The world of math does not
contain contradictions even though it may appear so at times. J
Chuanpu
From: Mark Sale [mailto:[email protected]]
Sent: Sunday, August 29, 2010 9:19 AM
To: Hu, Chuanpu [CNTUS]
Cc: nmusers
Subject: RE: [NMusers] Block versus diagonal omega
Chuanpu,
Do I extrapolate correctly then that:
V = THETA(1)*EXP(THETA(2)*ETA(1))
.
.
.
$OMEGA
(1,FIXED).
Can be tested (THETA(2) <> 0), since it is not a truncated distribution?
might be an interesting exercise to do this with LRT and compare to the
randomization test with the usual specification.
Mark
--- On Fri, 8/27/10, Hu, Chuanpu [CNTUS] <[email protected]> wrote:
From: Hu, Chuanpu [CNTUS] <[email protected]>
Subject: RE: [NMusers] Block versus diagonal omega
To: "Mark Sale - Next Level Solutions" <[email protected]>, "Eleveld,DJ"
<[email protected]>
Cc: "nmusers" <[email protected]>
Date: Friday, August 27, 2010, 4:33 PM
Theoretically, the NONMEM objective function drop for adding a diagonal element
follows a mixture chi-square distribution, from which follows that using the
“usual” chi-square distribution would be conservative. This has to do with 0
being on the boundary of possible values. (See Pinheiro and Bates, Mixed
Effects Models in S and S-PLUS, Springer, 2000.) As this boundary issue does
not apply to off-diagonal elements, the “usual” chi-square distribution should
be fine (with the usual statistical asymptotic caveats).
I’d like to mention that, while the “find the best fit” mindset may be suitable
for the typical exploratory setting, the p-values from repeated (e.g.,
stepwise) tests are not statistically interpretable. To have valid p-values,
confirmatory analyses would be needed, which in my mind deserves a wider use. J
Chuanpu
~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*
Chuanpu Hu, Ph.D.
Director, Pharmacometrics
Pharmacokinetics
Biologics Clinical Pharmacology
Janssen Pharmaceutical Companies of Johnson & Johnson
C-3-3
200 Great Valley Parkway
Malvern, PA 19355
Tel: 610-651-7423
Fax: (610) 993-7801
E-mail: [email protected]
~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*
Chuanpu,
In all stable problems that I tried, parametrization
ETA()
$OMEGA
0.1 ; estimated
was equivalent (in terms of the estimated value and objective function) to
THETA(*)*ETA()
$OMEGA
1 FIXED
Also,
H0: THETA=0, vs. H1: THETA<>0
is the same as
H0: OMEGA=0, vs. H1: OMEGA>0
since OMEGA=THETA^2
In theta-form, the problem has two identical solution
THETA()=SQRT(OMEGA) and THETA()= -SQRT(OMEGA)
Leonid
--------------------------------------
Leonid Gibiansky, Ph.D.
President, QuantPharm LLC
web: www.quantpharm.com
e-mail: LGibiansky at quantpharm.com
tel: (301) 767 5566
Quoted reply history
On 8/30/2010 1:41 PM, Hu, Chuanpu [CNTUS] wrote:
> *From:* Hu, Chuanpu [CNTUS]
> *Sent:* Monday, August 30, 2010 8:46 AM
> *To:* 'Mark Sale'
> *Cc:* 'nmusers'
> *Subject:* RE: [NMusers] Block versus diagonal omega
>
> Mark,
>
> Nice thought – the test can be conducted, but the devil is in the
> details. This has to do with the intricacies of the role alternative
> hypothesis plays in hypothesis testing:
>
> For the original parameterization testing OMEGA, the hypothesis test is
>
> H0: OMEGA=0, vs. H1: OMEGA>0
>
> For the THETA parameterization testing OMEGA, the hypothesis test is
>
> H0: THETA=0, vs. H1: THETA<>0
>
> So without getting into the math, the intuitive argument is that the
> alternative hypotheses in the 2 situations are different, therefore it
> is logical that the testing criteria must change. The world of math does
> not contain contradictions even though it may appear so at times. J
>
> Chuanpu
>
> *From:* Mark Sale [mailto:[email protected]]
> *Sent:* Sunday, August 29, 2010 9:19 AM
> *To:* Hu, Chuanpu [CNTUS]
> *Cc:* nmusers
> *Subject:* RE: [NMusers] Block versus diagonal omega
>
> Chuanpu,
> Do I extrapolate correctly then that:
>
> V = THETA(1)*EXP(THETA(2)*ETA(1))
> .
> .
> .
> $OMEGA
> (1,FIXED).
>
> Can be tested (THETA(2) <> 0), since it is not a truncated distribution?
> might be an interesting exercise to do this with LRT and compare to the
> randomization test with the usual specification.
>
> Mark
>
> --- On *Fri, 8/27/10, Hu, Chuanpu [CNTUS] /<[email protected]>/* wrote:
>
> From: Hu, Chuanpu [CNTUS] <[email protected]>
> Subject: RE: [NMusers] Block versus diagonal omega
> To: "Mark Sale - Next Level Solutions" <[email protected]>,
> "Eleveld,DJ" <[email protected]>
> Cc: "nmusers" <[email protected]>
> Date: Friday, August 27, 2010, 4:33 PM
>
> Theoretically, the NONMEM objective function drop for adding a diagonal
> element follows a mixture chi-square distribution, from which follows
> that using the “usual” chi-square distribution would be conservative.
> This has to do with 0 being on the boundary of possible values. (See
> Pinheiro and Bates, Mixed Effects Models in S and S-PLUS, Springer,
> 2000.) As this boundary issue does not apply to off-diagonal elements,
> the “usual” chi-square distribution should be fine (with the usual
> statistical asymptotic caveats).
>
> I’d like to mention that, while the “find the best fit” mindset may be
> suitable for the typical exploratory setting, the p-values from repeated
> (e.g., stepwise) tests are not statistically interpretable. To have
> valid p-values, confirmatory analyses would be needed, which in my mind
> deserves a wider use. J
>
> Chuanpu
>
> ~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*
>
> Chuanpu Hu, Ph.D.
>
> Director, Pharmacometrics
>
> Pharmacokinetics
>
> Biologics Clinical Pharmacology
>
> Janssen Pharmaceutical Companies of Johnson & Johnson
>
> C-3-3
>
> 200 Great Valley Parkway
>
> Malvern, PA 19355
>
> Tel: 610-651-7423
>
> Fax: (610) 993-7801
>
> E-mail: [email protected] </mc/[email protected]>
>
> ~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*
Hi Leonid,
Strictly speaking, when you use parameterization THETA(*)*ETA()
(actually I like this trick as well), you have to constraint THETA(*) to
be either positive or negative, otherwise this model has identifiability
issue. So still, the hypothesis shall be one-sided.
Thanks,
Yaming
Quoted reply history
-----Original Message-----
From: [email protected] [mailto:[email protected]]
On Behalf Of Leonid Gibiansky
Sent: Monday, August 30, 2010 2:48 PM
To: Hu, Chuanpu [CNTUS]
Cc: [email protected]
Subject: Re: FW: [NMusers] Block versus diagonal omega
Chuanpu,
In all stable problems that I tried, parametrization
ETA()
$OMEGA
0.1 ; estimated
was equivalent (in terms of the estimated value and objective function)
to
THETA(*)*ETA()
$OMEGA
1 FIXED
Also,
H0: THETA=0, vs. H1: THETA<>0
is the same as
H0: OMEGA=0, vs. H1: OMEGA>0
since OMEGA=THETA^2
In theta-form, the problem has two identical solution
THETA()=SQRT(OMEGA) and THETA()= -SQRT(OMEGA)
Leonid
--------------------------------------
Leonid Gibiansky, Ph.D.
President, QuantPharm LLC
web: www.quantpharm.com
e-mail: LGibiansky at quantpharm.com
tel: (301) 767 5566
On 8/30/2010 1:41 PM, Hu, Chuanpu [CNTUS] wrote:
> *From:* Hu, Chuanpu [CNTUS]
> *Sent:* Monday, August 30, 2010 8:46 AM
> *To:* 'Mark Sale'
> *Cc:* 'nmusers'
> *Subject:* RE: [NMusers] Block versus diagonal omega
>
> Mark,
>
> Nice thought - the test can be conducted, but the devil is in the
> details. This has to do with the intricacies of the role alternative
> hypothesis plays in hypothesis testing:
>
> For the original parameterization testing OMEGA, the hypothesis test
is
>
> H0: OMEGA=0, vs. H1: OMEGA>0
>
> For the THETA parameterization testing OMEGA, the hypothesis test is
>
> H0: THETA=0, vs. H1: THETA<>0
>
> So without getting into the math, the intuitive argument is that the
> alternative hypotheses in the 2 situations are different, therefore it
> is logical that the testing criteria must change. The world of math
does
> not contain contradictions even though it may appear so at times. J
>
> Chuanpu
>
> *From:* Mark Sale [mailto:[email protected]]
> *Sent:* Sunday, August 29, 2010 9:19 AM
> *To:* Hu, Chuanpu [CNTUS]
> *Cc:* nmusers
> *Subject:* RE: [NMusers] Block versus diagonal omega
>
> Chuanpu,
> Do I extrapolate correctly then that:
>
> V = THETA(1)*EXP(THETA(2)*ETA(1))
> .
> .
> .
> $OMEGA
> (1,FIXED).
>
> Can be tested (THETA(2) <> 0), since it is not a truncated
distribution?
> might be an interesting exercise to do this with LRT and compare to
the
> randomization test with the usual specification.
>
>
> Mark
>
>
> --- On *Fri, 8/27/10, Hu, Chuanpu [CNTUS] /<[email protected]>/*
wrote:
>
>
> From: Hu, Chuanpu [CNTUS] <[email protected]>
> Subject: RE: [NMusers] Block versus diagonal omega
> To: "Mark Sale - Next Level Solutions" <[email protected]>,
> "Eleveld,DJ" <[email protected]>
> Cc: "nmusers" <[email protected]>
> Date: Friday, August 27, 2010, 4:33 PM
>
> Theoretically, the NONMEM objective function drop for adding a
diagonal
> element follows a mixture chi-square distribution, from which follows
> that using the "usual" chi-square distribution would be conservative.
> This has to do with 0 being on the boundary of possible values. (See
> Pinheiro and Bates, Mixed Effects Models in S and S-PLUS, Springer,
> 2000.) As this boundary issue does not apply to off-diagonal elements,
> the "usual" chi-square distribution should be fine (with the usual
> statistical asymptotic caveats).
>
> I'd like to mention that, while the "find the best fit" mindset may be
> suitable for the typical exploratory setting, the p-values from
repeated
> (e.g., stepwise) tests are not statistically interpretable. To have
> valid p-values, confirmatory analyses would be needed, which in my
mind
> deserves a wider use. J
>
> Chuanpu
>
> ~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*
>
> Chuanpu Hu, Ph.D.
>
> Director, Pharmacometrics
>
> Pharmacokinetics
>
> Biologics Clinical Pharmacology
>
> Janssen Pharmaceutical Companies of Johnson & Johnson
>
> C-3-3
>
> 200 Great Valley Parkway
>
> Malvern, PA 19355
>
> Tel: 610-651-7423
>
> Fax: (610) 993-7801
>
> E-mail: [email protected] </mc/[email protected]>
>
> ~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*
>
Notice: This e-mail message, together with any attachments, contains
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Chuanpu, My experience is the same as Leonid's. I get the same OBJ, the same (transformed) parameters, with H(null) and H(alt). Hence my confusion, I get the same numbers, but one test of hypothesis is not valid (or perhaps conservative) and the other may be (noting that the distribution for THETA only makes sense if THETA is constrainted to be >0 or < 0, a distribution that crosses 0 seems meaningless to me). But, I'm usually not all that interested in testing hypotheses WRT OMEGA, and I'm pleased to learn that: 1. If you do a test of hypothesis it is conservative 2. AIC/BIC seem to still be valid indicators of "preference" WRT -2Loglikelihood change. Mark Sale MD Next Level Solutions, LLC www.NextLevelSolns.com 919-846-9185 A carbon-neutral company See our real time solar energy production at: http://enlighten.enphaseenergy.com/public/systems/aSDz2458
Quoted reply history
-------- Original Message --------
Subject: Re: FW: [NMusers] Block versus diagonal omega
From: Leonid Gibiansky < [email protected] >
Date: Mon, August 30, 2010 2:47 pm
To: "Hu, Chuanpu [CNTUS]" < [email protected] >
Cc: [email protected]
Chuanpu,
In all stable problems that I tried, parametrization
ETA()
$OMEGA
0.1 ; estimated
was equivalent (in terms of the estimated value and objective function) to
THETA(*)*ETA()
$OMEGA
1 FIXED
Also,
H0: THETA=0, vs. H1: THETA<>0
is the same as
H0: OMEGA=0, vs. H1: OMEGA>0
since OMEGA=THETA^2
In theta-form, the problem has two identical solution
THETA()=SQRT(OMEGA) and THETA()= -SQRT(OMEGA)
Leonid
--------------------------------------
Leonid Gibiansky, Ph.D.
President, QuantPharm LLC
web: www.quantpharm.com
e-mail: LGibiansky at quantpharm.com
tel: (301) 767 5566
On 8/30/2010 1:41 PM, Hu, Chuanpu [CNTUS] wrote:
> *From:* Hu, Chuanpu [CNTUS]
> *Sent:* Monday, August 30, 2010 8:46 AM
> *To:* 'Mark Sale'
> *Cc:* 'nmusers'
> *Subject:* RE: [NMusers] Block versus diagonal omega
>
> Mark,
>
> Nice thought – the test can be conducted, but the devil is in the
> details. This has to do with the intricacies of the role alternative
> hypothesis plays in hypothesis testing:
>
> For the original parameterization testing OMEGA, the hypothesis test is
>
> H0: OMEGA=0, vs. H1: OMEGA>0
>
> For the THETA parameterization testing OMEGA, the hypothesis test is
>
> H0: THETA=0, vs. H1: THETA<>0
>
> So without getting into the math, the intuitive argument is that the
> alternative hypotheses in the 2 situations are different, therefore it
> is logical that the testing criteria must change. The world of math does
> not contain contradictions even though it may appear so at times. J
>
> Chuanpu
>
> *From:* Mark Sale [ mailto: [email protected] ]
> *Sent:* Sunday, August 29, 2010 9:19 AM
> *To:* Hu, Chuanpu [CNTUS]
> *Cc:* nmusers
> *Subject:* RE: [NMusers] Block versus diagonal omega
>
> Chuanpu,
> Do I extrapolate correctly then that:
>
> V = THETA(1)*EXP(THETA(2)*ETA(1))
> .
> .
> .
> $OMEGA
> (1,FIXED).
>
> Can be tested (THETA(2) <> 0), since it is not a truncated distribution?
> might be an interesting exercise to do this with LRT and compare to the
> randomization test with the usual specification.
>
>
> Mark
>
>
> --- On *Fri, 8/27/10, Hu, Chuanpu [CNTUS] /< [email protected] >/* wrote:
>
>
> From: Hu, Chuanpu [CNTUS] < [email protected] >
> Subject: RE: [NMusers] Block versus diagonal omega
> To: "Mark Sale - Next Level Solutions" < [email protected] >,
> "Eleveld,DJ" < [email protected] >
> Cc: "nmusers" < [email protected] >
> Date: Friday, August 27, 2010, 4:33 PM
>
> Theoretically, the NONMEM objective function drop for adding a diagonal
> element follows a mixture chi-square distribution, from which follows
> that using the “usual” chi-square distribution would be conservative.
> This has to do with 0 being on the boundary of possible values. (See
> Pinheiro and Bates, Mixed Effects Models in S and S-PLUS, Springer,
> 2000.) As this boundary issue does not apply to off-diagonal elements,
> the “usual” chi-square distribution should be fine (with the usual
> statistical asymptotic caveats).
>
> I’d like to mention that, while the “find the best fit” mindset may be
> suitable for the typical exploratory setting, the p-values from repeated
> (e.g., stepwise) tests are not statistically interpretable. To have
> valid p-values, confirmatory analyses would be needed, which in my mind
> deserves a wider use. J
>
> Chuanpu
>
> ~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*
>
> Chuanpu Hu, Ph.D.
>
> Director, Pharmacometrics
>
> Pharmacokinetics
>
> Biologics Clinical Pharmacology
>
> Janssen Pharmaceutical Companies of Johnson & Johnson
>
> C-3-3
>
> 200 Great Valley Parkway
>
> Malvern, PA 19355
>
> Tel: 610-651-7423
>
> Fax: (610) 993-7801
>
> E-mail: [email protected] < /mc/ [email protected] >
>
> ~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*
>
Chuanpu,
These two problems (in OMEGA and THETA parametrizations) are identical (in a sense that they provide same parameter values and OF). Moreover, one can propose the third parametrization:
SQRT(THETA())*ETA()
$OMEGA
1 FIXED
with THETA() > 0 being the variance of the random effect (rather than SD). The tests based on them are either all valid, or all invalid.
I have not seen anybody going into that level of "rigorousness" as to analyze conditions when the OF follows theoretical chi^2 distribution (for each specific model parameter).
If so, we can use the same test for variances as well. The fact that we can does not imply that we should: in my experience, the number and the structure of random effects is defined mostly by the amount of individual data and stability of the problem (that is related to the amount of data). It may also be defined by the estimation method: newer methods allow (or even require) more complex OMEGA structure.
Thanks
Leonid
--------------------------------------
Leonid Gibiansky, Ph.D.
President, QuantPharm LLC
web: www.quantpharm.com
e-mail: LGibiansky at quantpharm.com
tel: (301) 767 5566
Quoted reply history
On 8/30/2010 4:22 PM, Hu, Chuanpu [CNTUS] wrote:
> Mark, Leonid et al,
>
> I guess my previous message was not clear. (And by the way, I have used
> something similar to the THETA-parameterization and observed the same
> NONMEM OBJF values, as should be.) The question is what distribution the
> NONMEM objective function difference follows. The proof of it being
> chi-square with 1 df requires certain mathematical “regularity
> conditions” that the THETA parameterization would violate (otherwise its
> distribution would not be a mixture chi-squire!). So, the hypothesis
> test based on OMEGA-parameterization is valid (with mixture
> chi-squared), and the test based on THETA-parameterization is invalid.
>
> Chuanpu
>
> *From:* [email protected]
> [mailto:[email protected]] *On Behalf Of *Mark Sale - Next
> Level Solutions
> *Sent:* Monday, August 30, 2010 3:55 PM
> *Cc:* [email protected]
> *Subject:* RE: FW: [NMusers] Block versus diagonal omega
>
> Chuanpu,
>
> My experience is the same as Leonid's. I get the same OBJ, the same
> (transformed) parameters, with H(null) and H(alt). Hence my confusion, I
> get the same numbers, but one test of hypothesis is not valid (or
> perhaps conservative) and the other may be (noting that the distribution
> for THETA only makes sense if THETA is constrainted to be >0 or < 0, a
> distribution that crosses 0 seems meaningless to me).
>
> But, I'm usually not all that interested in testing hypotheses WRT
> OMEGA, and I'm pleased to learn that:
>
> 1. If you do a test of hypothesis it is conservative
>
> 2. AIC/BIC seem to still be valid indicators of "preference" WRT
> -2Loglikelihood change.
>
> Mark Sale MD
> Next Level Solutions, LLC
> www.NextLevelSolns.com http://www.NextLevelSolns.com
> 919-846-9185
>
> A carbon-neutral company
>
> See our real time solar energy production at:
>
> http://enlighten.enphaseenergy.com/public/systems/aSDz2458
>
> -------- Original Message --------
> Subject: Re: FW: [NMusers] Block versus diagonal omega
> From: Leonid Gibiansky <[email protected]
> <mailto:[email protected]>>
> Date: Mon, August 30, 2010 2:47 pm
> To: "Hu, Chuanpu [CNTUS]" <[email protected] <mailto:[email protected]>>
> Cc: [email protected] <mailto:[email protected]>
>
> Chuanpu,
>
> In all stable problems that I tried, parametrization
>
> ETA()
> $OMEGA
> 0.1 ; estimated
>
> was equivalent (in terms of the estimated value and objective
> function) to
>
> THETA(*)*ETA()
> $OMEGA
> 1 FIXED
>
> Also,
>
> H0: THETA=0, vs. H1: THETA<>0
>
> is the same as
>
> H0: OMEGA=0, vs. H1: OMEGA>0
>
> since OMEGA=THETA^2
>
> In theta-form, the problem has two identical solution
>
> THETA()=SQRT(OMEGA) and THETA()= -SQRT(OMEGA)
>
> Leonid
>
> --------------------------------------
> Leonid Gibiansky, Ph.D.
> President, QuantPharm LLC
> web: www.quantpharm.com http://www.quantpharm.com
> e-mail: LGibiansky at quantpharm.com http://quantpharm.com
> tel: (301) 767 5566
Hi Leonid,
(I suspected this point might get belabored.) Applying the theory to the
THETA()>=0 parameterization obtains the mixture chi-square distribution, for
the same reason as the OMEGA case, hence results are indeed the same. Problem
arises only with interpreting THETA()<>0 and considering the LRT as a
chi-square distribution without mixture.
There is usually no need to worry about “regularity conditions”; they tend to
be easily satisfied for most practical scenarios. Although the boundary does
cause the issue (I hope it is clear now), other than this diagonal variance
testing case I really can see no reasons to be concerned. In addition, this
problem does not occur to off-diagonal elements (unless for some strange reason
you want to test a perfect correlation).
Whether parameters, OMEGA elements or not, “should” be included is a different
matter. The issues you mention, which I think in essence are numerical
approximation and how much “learning” to do, are obviously interesting, but
that is probably another topic..
Chuanpu
Quoted reply history
-----Original Message-----
From: [email protected] [mailto:[email protected]] On
Behalf Of Leonid Gibiansky
Sent: Monday, August 30, 2010 8:05 PM
To: Hu, Chuanpu [CNTUS]
Cc: Mark Sale - Next Level Solutions; [email protected]
Subject: Re: FW: [NMusers] Block versus diagonal omega
Chuanpu,
These two problems (in OMEGA and THETA parametrizations) are identical (in a
sense that they provide same parameter values and OF). Moreover, one can
propose the third parametrization:
SQRT(THETA())*ETA()
$OMEGA
1 FIXED
with THETA() > 0 being the variance of the random effect (rather than SD). The
tests based on them are either all valid, or all invalid.
I have not seen anybody going into that level of "rigorousness" as to analyze
conditions when the OF follows theoretical chi^2 distribution (for each
specific model parameter).
If so, we can use the same test for variances as well. The fact that we can
does not imply that we should: in my experience, the number and the structure
of random effects is defined mostly by the amount of individual data and
stability of the problem (that is related to the amount of data). It may also
be defined by the estimation method: newer methods allow (or even require) more
complex OMEGA structure.
Thanks
Leonid
--------------------------------------
Leonid Gibiansky, Ph.D.
President, QuantPharm LLC
web: www.quantpharm.com
e-mail: LGibiansky at quantpharm.com
tel: (301) 767 5566
On 8/30/2010 4:22 PM, Hu, Chuanpu [CNTUS] wrote:
> Mark, Leonid et al,
>
> I guess my previous message was not clear. (And by the way, I have
> used something similar to the THETA-parameterization and observed the
> same NONMEM OBJF values, as should be.) The question is what
> distribution the NONMEM objective function difference follows. The
> proof of it being chi-square with 1 df requires certain mathematical
> “regularity conditions” that the THETA parameterization would violate
> (otherwise its distribution would not be a mixture chi-squire!). So,
> the hypothesis test based on OMEGA-parameterization is valid (with
> mixture chi-squared), and the test based on THETA-parameterization is invalid.
>
> Chuanpu
Everyone -
Thank you all for your assistance in answering my question regarding the
block versus diagonal omega structure. The answers that you all
provided have been a great help thus far and are much appreciated. As a
follow-up, I was curious if someone could point me towards a reference
that would help me to figure out how to restructure the covariance into
different omega blocks. Specifically, I would like to understand the
basis and proper method for restructuring the omega block so that I may
remove selected covariance terms when simplifying from a completely
unstructured block to a more parsimonious one. Thanks again for your
help and time -
Al Berg
Hi Al,
You are probably looking for a band matrix, see the nonmem help entry on
$OMEGA:
"
An initial estimate of a diagonal block of the OMEGA matrix may have a
band symmetric form, in which case the final estimate has the same
form. E.g., with these structures for $OMEGA BLOCK(3), the 0's are
preserved:
x
0x
00x
x
xx
0xx
"
You can find a discussion on banded $OMEGA blocks with examples here:
http://www.cognigencorp.com/nonmem/nm/99jan012004.html ; keep this
http://www.mail-archive.com/[email protected]/msg00614.html in
mind.
Jeroen
Modeling & Simulation Expert
Pharmacokinetics, Pharmacodynamics & Pharmacometrics (P3) - DMPK
MSD
PO Box 20 - AP1112
5340 BH Oss
The Netherlands
[email protected]
T: +31 (0)412 66 9320
F: +31 (0)412 66 2506
www.msd.com
Quoted reply history
________________________________
From: [email protected] [mailto:[email protected]]
On Behalf Of Berg, Alexander K., Pharm.D., Ph.D.
Sent: Thursday, 02 September, 2010 22:40
To: [email protected]
Subject: RE: [NMusers] Block versus diagonal omega
Everyone -
Thank you all for your assistance in answering my question regarding the
block versus diagonal omega structure. The answers that you all
provided have been a great help thus far and are much appreciated. As a
follow-up, I was curious if someone could point me towards a reference
that would help me to figure out how to restructure the covariance into
different omega blocks. Specifically, I would like to understand the
basis and proper method for restructuring the omega block so that I may
remove selected covariance terms when simplifying from a completely
unstructured block to a more parsimonious one. Thanks again for your
help and time -
Al Berg
This message and any attachments are solely for the intended recipient. If you
are not the intended recipient, disclosure, copying, use or distribution of the
information included in this message is prohibited --- Please immediately and
permanently delete.
Hi Al,
as far as I can tell, if you have a BLOCK matrix in NONMEM, the only elements that you can fix to zero (without fixing the whole block) are the ones in the lower corner of the matrix. You can have lower triangular matrices of zeros as large as all of yours off-diagonal elements (in which case the matrix would become diagonal). To do this, you just set the initial estimate of those element to exactly zero. Don't write FIX anywhere in the block, or else NONMEM is going fix the values of the whole block.
Some examples would be
$OMEGA BLOCK(3)
a
b c
0 d e
or
$OMEGA BLOCK(4)
a
b c
0 d e
0 0 f g
or
$OMEGA BLOCK(4)
a
b c
d e f
0 g h j
Obviously, unless you are lucky, the zeros won't be where you want them to be with the numbering you chose for the ETAs, so you might need to change the order and bring all the zeros to the lower triangle. Lots of fun! ;)
Some matrices can't be obtained this way unless you sacrifice some additional correlations, I fear. Or at least I can't see how. Like the one below:
$OMEGA BLOCK(4)
a
b c
d e f
0 0 g h
The only way I can think to obtain exactly this one (someone else can maybe help here) is to calculate the Cholesky factor of your matrix so that you can rewrite it the whole thing in your code using only thetas. In that way you would be able free to fix whatever you want to any value.
Hope this is not too confusing...
Greetings from Cape Town,
Paolo
Quoted reply history
On 02/09/2010 22:39, Berg, Alexander K., Pharm.D., Ph.D. wrote:
> Everyone -
>
> Thank you all for your assistance in answering my question regarding the block versus diagonal omega structure. The answers that you all provided have been a great help thus far and are much appreciated. As a follow-up, I was curious if someone could point me towards a reference that would help me to figure out how to restructure the covariance into different omega blocks. Specifically, I would like to understand the basis and proper method for restructuring the omega block so that I may remove selected covariance terms when simplifying from a completely unstructured block to a more parsimonious one. Thanks again for your help and time -
>
> Al Berg
--
------------------------------------------------
Paolo Denti, PhD
Post-Doctoral Fellow
Division of Clinical Pharmacology
Department of Medicine
University of Cape Town
K45 Old Main Building
Groote Schuur Hospital
Observatory, Cape Town
7925 South Africa
phone: +27 21 404 7719
fax: +27 21 448 1989
email:[email protected]
All,
Just a reminder that NONMEM VI and NONMEM 7.1.0 have a bug that may
affect certain band matrices as noted in a previous bug alert (see
excerpt below). This has been corrected in NONMEM 7.1.2.
Tom
1. There is a bug in NONMEM VI 1.x & 2.0 and NONMEM 7.1.0 that
results in the spurious error message below, or a similar message,
when certain band symmetric matrices are defined in $OMEGA.
PROGRAM TERMINATED BY OBJ
OMEGA ESTIMATED TO BE SINGULAR
MESSAGE ISSUED FROM ESTIMATION STEP
AT INITIAL OBJ. FUNCTION EVALUATION
Workaround:
None is available.
Quoted reply history
________________________________
From: [email protected] [mailto:[email protected]]
On Behalf Of Paolo Denti
Sent: Friday, September 03, 2010 7:44 AM
To: nmusers
Subject: Re: [NMusers] Block versus diagonal omega
Hi Al,
as far as I can tell, if you have a BLOCK matrix in NONMEM, the only
elements that you can fix to zero (without fixing the whole block) are
the ones in the lower corner of the matrix.
You can have lower triangular matrices of zeros as large as all of yours
off-diagonal elements (in which case the matrix would become diagonal).
To do this, you just set the initial estimate of those element to
exactly zero. Don't write FIX anywhere in the block, or else NONMEM is
going fix the values of the whole block.
Some examples would be
$OMEGA BLOCK(3)
a
b c
0 d e
or
$OMEGA BLOCK(4)
a
b c
0 d e
0 0 f g
or
$OMEGA BLOCK(4)
a
b c
d e f
0 g h j
Obviously, unless you are lucky, the zeros won't be where you want them
to be with the numbering you chose for the ETAs, so you might need to
change the order and bring all the zeros to the lower triangle. Lots of
fun! ;)
Some matrices can't be obtained this way unless you sacrifice some
additional correlations, I fear. Or at least I can't see how. Like the
one below:
$OMEGA BLOCK(4)
a
b c
d e f
0 0 g h
The only way I can think to obtain exactly this one (someone else can
maybe help here) is to calculate the Cholesky factor of your matrix so
that you can rewrite it the whole thing in your code using only thetas.
In that way you would be able free to fix whatever you want to any
value.
Hope this is not too confusing...
Greetings from Cape Town,
Paolo
On 02/09/2010 22:39, Berg, Alexander K., Pharm.D., Ph.D. wrote:
Everyone -
Thank you all for your assistance in answering my question
regarding the block versus diagonal omega structure. The answers that
you all provided have been a great help thus far and are much
appreciated. As a follow-up, I was curious if someone could point me
towards a reference that would help me to figure out how to restructure
the covariance into different omega blocks. Specifically, I would like
to understand the basis and proper method for restructuring the omega
block so that I may remove selected covariance terms when simplifying
from a completely unstructured block to a more parsimonious one. Thanks
again for your help and time -
Al Berg
--
------------------------------------------------
Paolo Denti, PhD
Post-Doctoral Fellow
Division of Clinical Pharmacology
Department of Medicine
University of Cape Town
K45 Old Main Building
Groote Schuur Hospital
Observatory, Cape Town
7925 South Africa
phone: +27 21 404 7719
fax: +27 21 448 1989
email: [email protected]