FW: Block versus diagonal omega
From: Hu, Chuanpu [CNTUS]
Sent: Monday, August 30, 2010 8:46 AM
To: 'Mark Sale'
Cc: 'nmusers'
Subject: RE: [NMusers] Block versus diagonal omega
Mark,
Nice thought – the test can be conducted, but the devil is in the details. This
has to do with the intricacies of the role alternative hypothesis plays in
hypothesis testing:
For the original parameterization testing OMEGA, the hypothesis test is
H0: OMEGA=0, vs. H1: OMEGA>0
For the THETA parameterization testing OMEGA, the hypothesis test is
H0: THETA=0, vs. H1: THETA<>0
So without getting into the math, the intuitive argument is that the
alternative hypotheses in the 2 situations are different, therefore it is
logical that the testing criteria must change. The world of math does not
contain contradictions even though it may appear so at times. J
Chuanpu
From: Mark Sale [mailto:[email protected]]
Sent: Sunday, August 29, 2010 9:19 AM
To: Hu, Chuanpu [CNTUS]
Cc: nmusers
Subject: RE: [NMusers] Block versus diagonal omega
Chuanpu,
Do I extrapolate correctly then that:
V = THETA(1)*EXP(THETA(2)*ETA(1))
.
.
.
$OMEGA
(1,FIXED).
Can be tested (THETA(2) <> 0), since it is not a truncated distribution?
might be an interesting exercise to do this with LRT and compare to the
randomization test with the usual specification.
Mark
--- On Fri, 8/27/10, Hu, Chuanpu [CNTUS] <[email protected]> wrote:
From: Hu, Chuanpu [CNTUS] <[email protected]>
Subject: RE: [NMusers] Block versus diagonal omega
To: "Mark Sale - Next Level Solutions" <[email protected]>, "Eleveld,DJ"
<[email protected]>
Cc: "nmusers" <[email protected]>
Date: Friday, August 27, 2010, 4:33 PM
Theoretically, the NONMEM objective function drop for adding a diagonal element
follows a mixture chi-square distribution, from which follows that using the
“usual” chi-square distribution would be conservative. This has to do with 0
being on the boundary of possible values. (See Pinheiro and Bates, Mixed
Effects Models in S and S-PLUS, Springer, 2000.) As this boundary issue does
not apply to off-diagonal elements, the “usual” chi-square distribution should
be fine (with the usual statistical asymptotic caveats).
I’d like to mention that, while the “find the best fit” mindset may be suitable
for the typical exploratory setting, the p-values from repeated (e.g.,
stepwise) tests are not statistically interpretable. To have valid p-values,
confirmatory analyses would be needed, which in my mind deserves a wider use. J
Chuanpu
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Chuanpu Hu, Ph.D.
Director, Pharmacometrics
Pharmacokinetics
Biologics Clinical Pharmacology
Janssen Pharmaceutical Companies of Johnson & Johnson
C-3-3
200 Great Valley Parkway
Malvern, PA 19355
Tel: 610-651-7423
Fax: (610) 993-7801
E-mail: [email protected]
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