advan8 vs. advan13 (CORRECTION)

7 messages 5 people Latest: Nov 05, 2009

Re: advan8 vs. advan13 (CORRECTION)

From: Nick Holford Date: November 04, 2009 technical
Hi, Thanks to Peiming Ma and Thuy Vu for pointing out an error in my attempt to transform bioavailability into its logit. The logit transformation of a probability is ln(P/(1-P)) i.e. the log of the odds ratio. The reverse transform is correct i.e. exp(logit) is the odds ratio and P is then OR/(1+OR) (or 1/1+exp(-logit)). If THETA(1) is the bioavailability then this is (I hope) the correct transformation of THETA(1) and reverse transform to get the individual bioavailability with a random effect constrained to be within 0 and 1. MU_1=LOG(THETA(1)/(1-THETA(1)) ; logit of population bioavailability EXPP=MU_1+ETA(1) ; add random effect BIO=1/(1+EXP(-EXP(EXPP))) ; individual bioavailability Nick -- Nick Holford, Professor Clinical Pharmacology Dept Pharmacology & Clinical Pharmacology University of Auckland,85 Park Rd,Private Bag 92019,Auckland,New Zealand tel:+64(9)923-6730 fax:+64(9)373-7090 mobile:+64(21)46 23 53 email: n.holford http://www.fmhs.auckland.ac.nz/sms/pharmacology/holford

RE: FW: advan8 vs. advan13 (CORRECTION)

From: Robert Bauer Date: November 04, 2009 technical
Nick: Because EXPP could be highly negative, then EXP(-EXPP) has the potential to result in floating overflow. So, a filtering line would still be good. Using the logit code, the theta(1) would indeed be more easily interpretable. However, as you say, your theta would need to be constrained between 0 and 1 But, if we wish to retain linear mu modeling, something that is good to do for importance sampling, and sometimes essential for SAEM, then the parameterization I originally recommended would be most suitable: . MU_1=THETA(1) EXPP=MU_1+ETA(1) IE (EXPP>100.0) EXPP0.0 ;protect against floating overflow EXPW=EXP(EXPP) BIO=EXPW/(1.0+EXPW) or MU_1=THETA(1) EXPP=MU_1+ETA(1) IE (EXPP>100.0) EXPP0.0 ;protect against floating overflow EXPW=EXP(-EXPP) BIO=1/(1.0+EXPW) would be best. Furthermore, theta(1) itself may be negative infinity to positive infinity, so no boundaries are necessary to theta(1). All of these factors make the analysis particularly amenable to Gibbs sampling when doing BAYES analysis as well. Otherwise, non-linear mu/theta relationships and boundary imposing means Metropolis-Hastings sampling must be done, a less efficient process. When the analysis is done, the final result thetas could be transformed to more meaningful values: Thetap(1)=1/(1+exp(-theta(1))) and reported in that fashion. The transformation patterns after the individual subject parameter BIO and its relationship to theta. An appropriate propagation of errors algorithm would be used to transform the standard errors as well. Robert J. Bauer, Ph.D. Vice President, Pharmacometrics ICON Development Solutions Tel: (215) 616-6428 Mob: (925) 286-0769 Email: Robert.Bauer Web: www.icondevsolutions.com
Quoted reply history
________________________________ From: owner-nmusers On Behalf Of Nick Holford Sent: Wednesday, November 04, 2009 10:40 PM To: nmusers Subject: Re: FW: [NMusers] advan8 vs. advan13 (CORRECTION) Peiming, Thank you for pointing out my mistake again! Perhaps next time you should make the correction and send it to nmusers :-) MU_1=LOG(THETA(1)/(1-THETA(1)) ; logit of population bioavailability EXPP=MU_1+ETA(1) ; add random effect BIO=1/(1+EXP(-EXPP)) ; individual bioavailability Nick Ma, Peiming wrote: Unfortunately, Nick, you have an extra EXP: the denominator of BIO should be just 1 + EXP(-EXPP). :-) Cheers, ________________________________ From: owner-nmusers [mailto:owner-nmusers Sent: Wednesday, November 04, 2009 3:43 PM To: nmusers Subject: Re: [NMusers] advan8 vs. advan13 (CORRECTION) Hi, Thanks to Peiming Ma and Thuy Vu for pointing out an error in my attempt to transform bioavailability into its logit. The logit transformation of a probability is ln(P/(1-P)) i.e. the log of the odds ratio. The reverse transform is correct i.e. exp(logit) is the odds ratio and P is then OR/(1+OR) (or 1/1+exp(-logit)). If THETA(1) is the bioavailability then this is (I hope) the correct transformation of THETA(1) and reverse transform to get the individual bioavailability with a random effect constrained to be within 0 and 1. MU_1=LOG(THETA(1)/(1-THETA(1)) ; logit of population bioavailability EXPP=MU_1+ETA(1) ; add random effect BIO=1/(1+EXP(-EXP(EXPP))) ; individual bioavailability Nick -- Nick Holford, Professor Clinical Pharmacology Dept Pharmacology & Clinical Pharmacology University of Auckland,85 Park Rd,Private Bag 92019,Auckland,New Zealand tel:+64(9)923-6730 fax:+64(9)373-7090 mobile:+64(21)46 23 53 email: n.holford http://www.fmhs.auckland.ac.nz/sms/pharmacology/holford -- Nick Holford, Professor Clinical Pharmacology Dept Pharmacology & Clinical Pharmacology University of Auckland,85 Park Rd,Private Bag 92019,Auckland,New Zealand tel:+64(9)923-6730 fax:+64(9)373-7090 mobile:+64(21)46 23 53 email: n.holford http://www.fmhs.auckland.ac.nz/sms/pharmacology/holford

Re: advan8 vs. advan13 (CORRECTION)

From: Nick Holford Date: November 05, 2009 technical
Hi, Thanks to Peiming Ma and Thuy Vu for pointing out an error in my attempt to transform bioavailability into its logit. The logit transformation of a probability is ln(P/(1-P)) i.e. the log of the odds ratio. The reverse transform is correct i.e. exp(logit) is the odds ratio and P is then OR/(1+OR) (or 1/1+exp(-logit)). If THETA(1) is the bioavailability then this is (I hope) the correct transformation of THETA(1) and reverse transform to get the individual bioavailability with a random effect constrained to be within 0 and 1. MU_1=LOG(THETA(1)/(1-THETA(1)) ; logit of population bioavailability EXPP=MU_1+ETA(1) ; add random effect BIO=1/(1+EXP(-EXP(EXPP))) ; individual bioavailability Nick -- Nick Holford, Professor Clinical Pharmacology Dept Pharmacology & Clinical Pharmacology University of Auckland,85 Park Rd,Private Bag 92019,Auckland,New Zealand tel:+64(9)923-6730 fax:+64(9)373-7090 mobile:+64(21)46 23 53 email: [email protected] http://www.fmhs.auckland.ac.nz/sms/pharmacology/holford

Re: FW: advan8 vs. advan13 (CORRECTION)

From: Leonid Gibiansky Date: November 05, 2009 technical
Bob, You seems to protect only from positive x=infinity overflow Do we also need to worry about negatives x=-infinity? If yes, we also need lines: IF (EXPP<-100.0) EXPP=-100.0 ;protect against floating overflow If not, then the second part of the code: > EXPP=MU_1+ETA(1) > IF (EXPP>100.0) EXPP0.0 ;protect against floating overflow > EXPW=EXP(-EXPP) protects from the wrong overflow, it needs to be replaced by > IF (EXPP<-100.0) EXPP=-100.0 ;protect against floating overflow Leonid -------------------------------------- Leonid Gibiansky, Ph.D. President, QuantPharm LLC web: www.quantpharm.com e-mail: LGibiansky at quantpharm.com tel: (301) 767 5566 Bauer, Robert wrote: > Nick: > Because EXPP could be highly negative, then EXP(-EXPP) has the potential > to result in floating overflow. So, a filtering line would still be good. > ** > Using the logit code, the theta(1) would indeed be more easily > interpretable. However, as you say, your theta would need to be > constrained between 0 and 1 > > But, if we wish to retain linear mu modeling, something that is good to > do for importance sampling, and sometimes essential for SAEM, then > the parameterization I originally recommended would be most suitable: . > > MU_1=THETA(1) > EXPP=MU_1+ETA(1) > IE (EXPP>100.0) EXPP0.0 ;protect against floating overflow > EXPW=EXP(EXPP) > BIO=EXPW/(1.0+EXPW) > > or > MU_1=THETA(1) > EXPP=MU_1+ETA(1) > IE (EXPP>100.0) EXPP0.0 ;protect against floating overflow > EXPW=EXP(-EXPP) > BIO=1/(1.0+EXPW) > > would be best. Furthermore, theta(1) itself may be negative infinity to > positive infinity, so no boundaries are necessary to theta(1). All of > these factors make the analysis particularly amenable to Gibbs sampling > when doing BAYES analysis as well. Otherwise, non-linear mu/theta > relationships and boundary imposing means Metropolis-Hastings sampling > must be done, a less efficient process. > > When the analysis is done, the final result thetas could be transformed > to more meaningful values: > > Thetap(1)=1/(1+exp(-theta(1))) > > and reported in that fashion. The transformation patterns after the > individual subject parameter BIO and its relationship to theta. > An appropriate propagation of errors algorithm would be used to > transform the standard errors as well. > > > *Robert J. Bauer, Ph.D. > Vice President, Pharmacometrics > ICON Development Solutions* > > *Tel:* (215) 616-6428 > *Mob: *(925) 286-0769 > *Email: Robert.Bauer > *Web:* www.icondevsolutions.com > > > > > > > > ------------------------------------------------------------------------ > *From:* owner-nmusers > [mailto:owner-nmusers > *Sent:* Wednesday, November 04, 2009 10:40 PM > *To:* nmusers > *Subject:* Re: FW: [NMusers] advan8 vs. advan13 (CORRECTION) > > Peiming, > > Thank you for pointing out my mistake again! > > Perhaps next time you should make the correction and send it to nmusers :-) > > MU_1=LOG(THETA(1)/(1-THETA(1)) ; logit of population bioavailability > > EXPP=MU_1+ETA(1) ; add random effect > > BIO=1/(1+EXP(-EXPP)) ; individual bioavailability > > > > Nick > > Ma, Peiming wrote: >> >> Unfortunately, Nick, you have an extra EXP: the denominator of BIO >> should be just 1 + EXP(-EXPP). J >> >> Cheers, >> >> ------------------------------------------------------------------------ >> >> *From:* owner-nmusers >> [mailto:owner-nmusers >> *Sent:* Wednesday, November 04, 2009 3:43 PM >> *To:* nmusers >> *Subject:* Re: [NMusers] advan8 vs. advan13 (CORRECTION) >> >> Hi, >> >> Thanks to Peiming Ma and Thuy Vu for pointing out an error in my >> attempt to transform bioavailability into its logit. >> >> The logit transformation of a probability is ln(P/(1-P)) i.e. the log >> of the odds ratio. The reverse transform is correct i.e. exp(logit) is >> the odds ratio and P is then OR/(1+OR) (or 1/1+exp(-logit)). >> >> If THETA(1) is the bioavailability then this is (I hope) the correct >> transformation of THETA(1) and reverse transform to get the >> individual bioavailability with a random effect constrained to be >> within 0 and 1. >> >> MU_1=LOG(THETA(1)/(1-THETA(1)) ; logit of population bioavailability >> >> EXPP=MU_1+ETA(1) ; add random effect >> >> BIO=1/(1+EXP(-EXP(EXPP))) ; individual bioavailability >> >> >> Nick >> >> -- >> Nick Holford, Professor Clinical Pharmacology >> Dept Pharmacology & Clinical Pharmacology >> University of Auckland,85 Park Rd,Private Bag 92019,Auckland,New Zealand >> tel:+64(9)923-6730 fax:+64(9)373-7090 mobile:+64(21)46 23 53 >> email: n.holford >> http://www.fmhs.auckland.ac.nz/sms/pharmacology/holford > > -- > Nick Holford, Professor Clinical Pharmacology > Dept Pharmacology & Clinical Pharmacology > University of Auckland,85 Park Rd,Private Bag 92019,Auckland,New Zealand > tel:+64(9)923-6730 fax:+64(9)373-7090 mobile:+64(21)46 23 53 > email: n.holford > http://www.fmhs.auckland.ac.nz/sms/pharmacology/holford > >

RE: FW: advan8 vs. advan13 (CORRECTION)

From: Robert Bauer Date: November 05, 2009 technical
Leonid: Agreed. Robert J. Bauer, Ph.D. Vice President, Pharmacometrics ICON Development Solutions Tel: (215) 616-6428 Mob: (925) 286-0769 Email: Robert.Bauer Web: www.icondevsolutions.com
Quoted reply history
-----Original Message----- From: Leonid Gibiansky [mailto:LGibiansky Sent: Thursday, November 05, 2009 6:20 AM To: Bauer, Robert Cc: Nick Holford; nmusers Subject: Re: FW: [NMusers] advan8 vs. advan13 (CORRECTION) Bob, You seems to protect only from positive x=infinity overflow Do we also need to worry about negatives x=-infinity? If yes, we also need lines: IF (EXPP<-100.0) EXPP=-100.0 ;protect against floating overflow If not, then the second part of the code: > EXPP=MU_1+ETA(1) > IF (EXPP>100.0) EXPP0.0 ;protect against floating overflow > EXPW=EXP(-EXPP) protects from the wrong overflow, it needs to be replaced by > IF (EXPP<-100.0) EXPP=-100.0 ;protect against floating overflow Leonid -------------------------------------- Leonid Gibiansky, Ph.D. President, QuantPharm LLC web: www.quantpharm.com e-mail: LGibiansky at quantpharm.com tel: (301) 767 5566 Bauer, Robert wrote: > Nick: > Because EXPP could be highly negative, then EXP(-EXPP) has the potential > to result in floating overflow. So, a filtering line would still be good. > ** > Using the logit code, the theta(1) would indeed be more easily > interpretable. However, as you say, your theta would need to be > constrained between 0 and 1 > > But, if we wish to retain linear mu modeling, something that is good to > do for importance sampling, and sometimes essential for SAEM, then > the parameterization I originally recommended would be most suitable: . > > MU_1=THETA(1) > EXPP=MU_1+ETA(1) > IE (EXPP>100.0) EXPP0.0 ;protect against floating overflow > EXPW=EXP(EXPP) > BIO=EXPW/(1.0+EXPW) > > or > MU_1=THETA(1) > EXPP=MU_1+ETA(1) > IE (EXPP>100.0) EXPP0.0 ;protect against floating overflow > EXPW=EXP(-EXPP) > BIO=1/(1.0+EXPW) > > would be best. Furthermore, theta(1) itself may be negative infinity to > positive infinity, so no boundaries are necessary to theta(1). All of > these factors make the analysis particularly amenable to Gibbs sampling > when doing BAYES analysis as well. Otherwise, non-linear mu/theta > relationships and boundary imposing means Metropolis-Hastings sampling > must be done, a less efficient process. > > When the analysis is done, the final result thetas could be transformed > to more meaningful values: > > Thetap(1)=1/(1+exp(-theta(1))) > > and reported in that fashion. The transformation patterns after the > individual subject parameter BIO and its relationship to theta. > An appropriate propagation of errors algorithm would be used to > transform the standard errors as well. > > > *Robert J. Bauer, Ph.D. > Vice President, Pharmacometrics > ICON Development Solutions* > > *Tel:* (215) 616-6428 > *Mob: *(925) 286-0769 > *Email: Robert.Bauer > *Web:* www.icondevsolutions.com > > > > > > > > ------------------------------------------------------------------------ > *From:* owner-nmusers > [mailto:owner-nmusers > *Sent:* Wednesday, November 04, 2009 10:40 PM > *To:* nmusers > *Subject:* Re: FW: [NMusers] advan8 vs. advan13 (CORRECTION) > > Peiming, > > Thank you for pointing out my mistake again! > > Perhaps next time you should make the correction and send it to nmusers :-) > > MU_1=LOG(THETA(1)/(1-THETA(1)) ; logit of population bioavailability > > EXPP=MU_1+ETA(1) ; add random effect > > BIO=1/(1+EXP(-EXPP)) ; individual bioavailability > > > > Nick > > Ma, Peiming wrote: >> >> Unfortunately, Nick, you have an extra EXP: the denominator of BIO >> should be just 1 + EXP(-EXPP). J >> >> Cheers, >> >> ------------------------------------------------------------------------ >> >> *From:* owner-nmusers >> [mailto:owner-nmusers >> *Sent:* Wednesday, November 04, 2009 3:43 PM >> *To:* nmusers >> *Subject:* Re: [NMusers] advan8 vs. advan13 (CORRECTION) >> >> Hi, >> >> Thanks to Peiming Ma and Thuy Vu for pointing out an error in my >> attempt to transform bioavailability into its logit. >> >> The logit transformation of a probability is ln(P/(1-P)) i.e. the log >> of the odds ratio. The reverse transform is correct i.e. exp(logit) is >> the odds ratio and P is then OR/(1+OR) (or 1/1+exp(-logit)). >> >> If THETA(1) is the bioavailability then this is (I hope) the correct >> transformation of THETA(1) and reverse transform to get the >> individual bioavailability with a random effect constrained to be >> within 0 and 1. >> >> MU_1=LOG(THETA(1)/(1-THETA(1)) ; logit of population bioavailability >> >> EXPP=MU_1+ETA(1) ; add random effect >> >> BIO=1/(1+EXP(-EXP(EXPP))) ; individual bioavailability >> >> >> Nick >> >> -- >> Nick Holford, Professor Clinical Pharmacology >> Dept Pharmacology & Clinical Pharmacology >> University of Auckland,85 Park Rd,Private Bag 92019,Auckland,New Zealand >> tel:+64(9)923-6730 fax:+64(9)373-7090 mobile:+64(21)46 23 53 >> email: n.holford >> http://www.fmhs.auckland.ac.nz/sms/pharmacology/holford > > -- > Nick Holford, Professor Clinical Pharmacology > Dept Pharmacology & Clinical Pharmacology > University of Auckland,85 Park Rd,Private Bag 92019,Auckland,New Zealand > tel:+64(9)923-6730 fax:+64(9)373-7090 mobile:+64(21)46 23 53 > email: n.holford > http://www.fmhs.auckland.ac.nz/sms/pharmacology/holford > >

RE: advan8 vs. advan13 (CORRECTION)

From: Jurgen Bulitta Date: November 05, 2009 technical
Dear Bob, Dear Nick, Dear Leonid, Thank you very much for showing us this trick. Will be happy to try this both-sided protection feature. In my experience with MC-PEM in S-ADAPT, I did not have any problems even with the unprotected version of the code proposed by Bob: MU_1=THETA(1) EXPP=MU_1+ETA(1) EXPW=EXP(-EXPP) BIO=1/(1.0+EXPW) I agree that one should take much more care to write robust / protected code with MC-PEM than with FOCE, for example. Best wishes Juergen
Quoted reply history
-----Original Message----- From: owner-nmusers Behalf Of Bauer, Robert Sent: Thursday, November 05, 2009 9:01 AM To: Leonid Gibiansky Cc: Nick Holford; nmusers Subject: RE: [NMusers] advan8 vs. advan13 (CORRECTION) Leonid: Agreed. Robert J. Bauer, Ph.D. Vice President, Pharmacometrics ICON Development Solutions Tel: (215) 616-6428 Mob: (925) 286-0769 Email: Robert.Bauer Web: www.icondevsolutions.com -----Original Message----- From: Leonid Gibiansky [mailto:LGibiansky Sent: Thursday, November 05, 2009 6:20 AM To: Bauer, Robert Cc: Nick Holford; nmusers Subject: Re: FW: [NMusers] advan8 vs. advan13 (CORRECTION) Bob, You seems to protect only from positive x=infinity overflow Do we also need to worry about negatives x=-infinity? If yes, we also need lines: IF (EXPP<-100.0) EXPP=-100.0 ;protect against floating overflow If not, then the second part of the code: > EXPP=MU_1+ETA(1) > IF (EXPP>100.0) EXPP0.0 ;protect against floating overflow > EXPW=EXP(-EXPP) protects from the wrong overflow, it needs to be replaced by > IF (EXPP<-100.0) EXPP=-100.0 ;protect against floating overflow Leonid -------------------------------------- Leonid Gibiansky, Ph.D. President, QuantPharm LLC web: www.quantpharm.com e-mail: LGibiansky at quantpharm.com tel: (301) 767 5566 Bauer, Robert wrote: > Nick: > Because EXPP could be highly negative, then EXP(-EXPP) has the potential > to result in floating overflow. So, a filtering line would still be good. > ** > Using the logit code, the theta(1) would indeed be more easily > interpretable. However, as you say, your theta would need to be > constrained between 0 and 1 > > But, if we wish to retain linear mu modeling, something that is good to > do for importance sampling, and sometimes essential for SAEM, then > the parameterization I originally recommended would be most suitable: . > > MU_1=THETA(1) > EXPP=MU_1+ETA(1) > IE (EXPP>100.0) EXPP0.0 ;protect against floating overflow > EXPW=EXP(EXPP) > BIO=EXPW/(1.0+EXPW) > > or > MU_1=THETA(1) > EXPP=MU_1+ETA(1) > IE (EXPP>100.0) EXPP0.0 ;protect against floating overflow > EXPW=EXP(-EXPP) > BIO=1/(1.0+EXPW) > > would be best. Furthermore, theta(1) itself may be negative infinity to > positive infinity, so no boundaries are necessary to theta(1). All of > these factors make the analysis particularly amenable to Gibbs sampling > when doing BAYES analysis as well. Otherwise, non-linear mu/theta > relationships and boundary imposing means Metropolis-Hastings sampling > must be done, a less efficient process. > > When the analysis is done, the final result thetas could be transformed > to more meaningful values: > > Thetap(1)=1/(1+exp(-theta(1))) > > and reported in that fashion. The transformation patterns after the > individual subject parameter BIO and its relationship to theta. > An appropriate propagation of errors algorithm would be used to > transform the standard errors as well. > > > *Robert J. Bauer, Ph.D. > Vice President, Pharmacometrics > ICON Development Solutions* > > *Tel:* (215) 616-6428 > *Mob: *(925) 286-0769 > *Email: Robert.Bauer > *Web:* www.icondevsolutions.com > > > > > > > > ------------------------------------------------------------------------ > *From:* owner-nmusers > [mailto:owner-nmusers > *Sent:* Wednesday, November 04, 2009 10:40 PM > *To:* nmusers > *Subject:* Re: FW: [NMusers] advan8 vs. advan13 (CORRECTION) > > Peiming, > > Thank you for pointing out my mistake again! > > Perhaps next time you should make the correction and send it to nmusers :-) > > MU_1=LOG(THETA(1)/(1-THETA(1)) ; logit of population bioavailability > > EXPP=MU_1+ETA(1) ; add random effect > > BIO=1/(1+EXP(-EXPP)) ; individual bioavailability > > > > Nick > > Ma, Peiming wrote: >> >> Unfortunately, Nick, you have an extra EXP: the denominator of BIO >> should be just 1 + EXP(-EXPP). J >> >> Cheers, >> >> ------------------------------------------------------------------------ >> >> *From:* owner-nmusers >> [mailto:owner-nmusers >> *Sent:* Wednesday, November 04, 2009 3:43 PM >> *To:* nmusers >> *Subject:* Re: [NMusers] advan8 vs. advan13 (CORRECTION) >> >> Hi, >> >> Thanks to Peiming Ma and Thuy Vu for pointing out an error in my >> attempt to transform bioavailability into its logit. >> >> The logit transformation of a probability is ln(P/(1-P)) i.e. the log >> of the odds ratio. The reverse transform is correct i.e. exp(logit) is >> the odds ratio and P is then OR/(1+OR) (or 1/1+exp(-logit)). >> >> If THETA(1) is the bioavailability then this is (I hope) the correct >> transformation of THETA(1) and reverse transform to get the >> individual bioavailability with a random effect constrained to be >> within 0 and 1. >> >> MU_1=LOG(THETA(1)/(1-THETA(1)) ; logit of population bioavailability >> >> EXPP=MU_1+ETA(1) ; add random effect >> >> BIO=1/(1+EXP(-EXP(EXPP))) ; individual bioavailability >> >> >> Nick >> >> -- >> Nick Holford, Professor Clinical Pharmacology >> Dept Pharmacology & Clinical Pharmacology >> University of Auckland,85 Park Rd,Private Bag 92019,Auckland,New Zealand >> tel:+64(9)923-6730 fax:+64(9)373-7090 mobile:+64(21)46 23 53 >> email: n.holford >> http://www.fmhs.auckland.ac.nz/sms/pharmacology/holford > > -- > Nick Holford, Professor Clinical Pharmacology > Dept Pharmacology & Clinical Pharmacology > University of Auckland,85 Park Rd,Private Bag 92019,Auckland,New Zealand > tel:+64(9)923-6730 fax:+64(9)373-7090 mobile:+64(21)46 23 53 > email: n.holford > http://www.fmhs.auckland.ac.nz/sms/pharmacology/holford > >

RE: advan8 vs. advan13 (CORRECTION)

From: Stephen Duffull Date: November 05, 2009 technical
Juergen (Bob, Nick, Leonid) FYI: In WinBUGS I also don't get problems with: > MU_1=THETA(1) > EXPP=MU_1+ETA(1) > EXPW=EXP(-EXPP) > BIO=1/(1.0+EXPW) Regards Steve -- Professor Stephen Duffull Chair of Clinical Pharmacy School of Pharmacy University of Otago PO Box 913 Dunedin New Zealand E: [email protected] P: +64 3 479 5044 F: +64 3 479 7034 Design software: www.winpopt.com