help with indirect reponse model

From: Zheng Lu Date: November 28, 2007 technical Source: mail-archive.com
Dear all: With the following code and data, the predicted fit is poor and no standard error output for parameter. I highly appreciate your kind help. Thanks a lot in your busy time. $PROB PLK INDIRECT RESPONSE MODEL $INPUT ID TIME DV AMT CMT $DATA PLKDOSE10SIMUL.CSV IGNORE=C $SUBROUTINE ADVAN6 TOL=5 $MODEL COMP=(CENTRAL,DEFDOSE) COMP=PERIPH COMP=EFFECT $PK K10=THETA(1)*EXP(ETA(1)) V1=THETA(2)*EXP(ETA(2)) K12=THETA(3)*EXP(ETA(3)) K21=THETA(4)*EXP(ETA(4)) SYNTH=THETA(5)*EXP(ETA(5)) LOSS=SYNTH IC50=THETA(6)*EXP(ETA(6)) S1=V1 $DES DADT(1)=K21*A(2)-(K12+K10)*A(1) DADT(2)=K12*A(1)-K21*A(2) INH=IC50/(IC50+A(1)/S1) DADT(3)=SYNTH-LOSS*INH*A(3) $ERROR CP=A(1)/S1 Q=1 IF (CMT .EQ. 2) Q=0 Y=Q*F*EXP(ERR(1))+(1-Q)*F*EXP(ERR(2)) IPRE=Y $THETA (0,1.3) ;K10 (0,3) ;S1 (0,0.3) ;K12 (0,0.37) ;K21 (0,1) ;SYNTH (0,10) ;IC50 $OMEGA 0 FIX 0 FIX 0 FIX 0 FIX 0 FIX 0 FIX $SIGMA 0.04 0.5 $ESTIMATION MAXEVAL=9999 POSTHOC PRINT=5 $COV $TABLE NOPRINT FILE=PLKPKPD.txt ONEHEADER ID TIME AMT CMT CP IPRE CID TIME DV AMT CMT 1 0 0 16807 1 1 0 0 1 3 1 0 5 0 3 1 0.0833 4403 0 1 1 0.0833 5.82 0 3 1 0.5 2007 0 1 1 0.5 5.23 0 3 1 1 948 0 1 1 1 8.1 0 3 1 2 323 0 1 1 2 8.99 0 3 1 8 27 0 1 1 8 15.86 0 3 1 16 3 0 1 1 16 33.39 0 3 1 24 33.75 0 3 1 48 24.19 0 3 1 72 10.43 0 3 1 96 8.03 0 3 lu
Nov 28, 2007 Zheng Lu help with indirect reponse model
Nov 28, 2007 Jurgen Bulitta Re: help with indirect reponse model
Nov 28, 2007 Nick Holford Re: help with indirect reponse model