Question re: indirect model

From: Jocelyn Leu Date: January 05, 2004 technical Source: cognigencorp.com
From: Jocelyn Leu - josniko@hotmail.com Subject: [NMusers] Question re: indirect model Date: 1/5/2004 10:38 AM I am forwarding this message for Dr. Xu who is joining the NM user group in case his email did not post yet. Dear NM Users: I encountered difficulty in coding a control file for simultaneous PK/PD modeling using differential equations (ADVAN6, one-compartment PK model with oral dosing, and indirectPD modeling (inhibition of Kin) for endogenous substance: In this case, both drug concentration and drug response occur in the central compartment-- for which I guess that I have to treat them as two different types of observations). You will be profoundly appreciated if you send me a sample control stream file of NONMEM for a similar situation (if something particular for the data file, please also indicate so). I also enclose the data file and the model control stream for you to revise it (though it may not be helpful at all). The dose unit is mg, and the PK concentration is in ng/ml. When Type=0, DV is drug concentration; while DV is PD marker when type is 1. Again, thank you so much. Michael Xu Control Stream ;Model Desc: one-com PK/indirect PD DIFF ;Project Name: XUPPD700 ;Project ID: PPD700 VERSUS EFFECT $PROB RUN# 101 ADVAN6 $INPUT C ID AMT TIME DV TYPE CMT $DATA 101.csv IGNORE=C $SUBROUTINE ADVAN6 TRANS=1 TOL=3 $MODEL NCOMP=2 COMP=(GUT) COMP=(CENTRAL) $PK KA=THETA(1)*EXP(ETA(1)) KE=THETA(2)*EXP(ETA(2)) V2=THETA(3)*EXP(ETA(3)) IF (TYPE.EQ.0) THEN S2=V2/1000 ELSE S2=1 ENDIF KIN=THETA(4)*EXP(ETA(4)) KOUT=THETA(5)*EXP(ETA(5)) IC50=THETA(6)*EXP(ETA(6)) $DES ;PK MODEL DADT(1)=-KA*A(1) IF (TYPE.EQ.0) THEN DADT(2)=KA*A(1)-KE*A(2) CP=A(2)/S2 ;PD MODEL EFF=CP/(CP + IC50) ELSE DADT(2)=KIN* (1-EFF)- KOUT*A(2) ENDIF $ERROR ;TYPE=0 FOR CP, TYPE=1 FOR E Y=F*EXP(ERR(1)) IPRED=F $THETA (0,10) ;KA (0,0.5) ;KE (0,1000) ;V2 (0,100) ;KIN (0,1) ;KOUT (0,100) ;EC50 $OMEGA 0.01 ;[P] 0.01 ;[P] 0.01 ;[P] 0.01 ;[P] 0.04 ;[P] 0.04 ;[P] $SIGMA 0.01 ;[P] $ESTIMATION MAXEVAL=9999 PRINT=5 MSF=101.msf POSTHOC $COV $TABLE ID TIME DV PRED IPRED TYPE CMT FILE=101.tab NOPRINT
Jan 05, 2004 Jocelyn Leu Question re: indirect model
Jan 07, 2004 Vgcasabo RE: Question re: indirect model