linear relation

From: Hauke Rühs Date: October 13, 2010 technical Source: mail-archive.com
Dear NMusers, I currently building an indirect response model C1=A(1)/V1 DADT(2)=KIN-KOUT*INH*A(2) , where the KOUT is inhibited by INH=1-(SLOPE*C1). SLOPE should be estimated with variability. How can I make sure that INH stays between 0 and 1? I wrote it like this IF ((SLOPE*C1).GT.1) THEN INH=0 ENDIF IF ((SLOPE*C1).LT.0) THEN INH=1 ENDIF IF((SLOPE*C1).LE.1.AND.(SLOPE*C1).GE.0) THEN INH=1-SLOPE*C1 ENDIF , but I think it is not optimal to write it in conditions. Does anyone know a better way to write this? Thank you. ----------------------------- Hauke Rühs Apotheker Pharmazeutisches Institut - Klinische Pharmazie - An der Immenburg 4 53121 Bonn Tel: + 49-(0)228 73-5781 Fax: + 49-(0)228 73-9757 http://www.klinische-pharmazie.info/ www.klinische-pharmazie.info
Oct 13, 2010 Hauke Rühs linear relation
Oct 13, 2010 Jun Shen Re: linear relation