RE: Dynamic enzymatic model

From: Ekaterina Gibiansky Date: July 22, 2009 technical Source: mail-archive.com
Christian, Is this infusion or oral dosing? If infusion, you need RATE data item, if oral, you need absorption compartment. Also, there is a problem with volumes. If A(1 ) and A(2) are amounts and A(3) is concentration of the complex, you need to multiply KE2 * A(3) by V3 in equation 2. And divide KE1 * B*A(1) by V1 in equation 3. Also, the enzyme reaction is happening in the same volume, so V1, V2 and V3 should be the same. And computations should be in molar amounts (scaling parameters can take care of this if AMT and DV are not in molar units). Regards, Katya ------------------------------------- Ekaterina Gibiansky, PhD Senior Scientific Director, PKPD, Modeling & Simulation ICON Development Solutions Email: [email protected] <mailto:[email protected]>
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________________________________ From: [email protected] [mailto:[email protected]] On Behalf Of christian woloch Sent: Wednesday, July 22, 2009 5:46 AM To: [email protected] Subject: [NMusers] Dynamic enzymatic model Dear all, I try to model simultaneously a parent drug and its metabolite using a 2 compartments dynamic enzymatic model (using the general enzymatic reaction E+S-->(ES)-->E+P). Here is the control stream : $PROB TEST MODELISATION NLIN 2CPMT $INPUT ID TIME DV AMT MDV CMT $DATA DATA131.csv IGNORE=# $SUBROUTINE ADVAN8 TOL4 ; Modèle Non linéaire 2 cpts $MODEL COMP= (CENTRAL,DEFDOSE) ; cpt 5FU COMP= (CENTRAL,NODOSE) ; cpt 5FDHU COMP= (CENTRAL,NODOSE) ; enzyme **(1)** $PK V1 =THETA(1)*EXP(ETA(1)) ; Vd 5FU V2 =THETA(2)*EXP(ETA(2)) ; Vd 5FDHU CL10 =THETA(3)*EXP(ETA(3)) ; Cl d'élimination 5FU CL20 =THETA(4)*EXP(ETA(4)) ; Cl d'élimination 5FDHU KE1 =THETA(5)*EXP(ETA(5)) ; Cstte de métabolisation KE2 =THETA(6)*EXP(ETA(6)) ; Cstte de métabolisation ET =THETA(7)*EXP(ETA(7)) ; total enzyme K10=CL10/V1 K20=CL20/V2 S1=V1 S2=V2 $DES B= ET-A(3) DADT(1)= -K10 *A(1)-KE1*B*A(1) DADT(2)= KE2 * A(3) - K20 * A(2) DADT(3)= KE1 * B*A(1)-KE2*A(3) $ERROR IPRED=F IF (CMT.EQ.1) THEN Y=F*(1+EPS(1))+ EPS(2) ELSE Y=F*(1+EPS(3)) ENDIF IRES=DV-IPRED $THETA (0,10,20) (0,60,100) (0,1,10) (0,1,10) (0,1,10) (0,1,10) (0,1,10) $OMEGA (1) (1) (1) (1) (1) (1) (1) $SIGMA (0.01) (0.01) (0.01) $EST METHOD=1 SIG=3 MAXEVAL=9999 **(1)** : this compartment was added because of the enzyme own equation (DADT(3)). With FO, I'm trying to estimate the parameters But with FOCE, the run stop immediately! ERROR IN NCONTR WITH INDIVIDUAL 1 ID=0.10000000E+01 NUMERICAL HESSIAN OF OBJ. FUNC. FOR COMPUTING CONDITIONAL ESTIMATE IS NON POSITIVE DEFINITE 1)Are there any problems in the control stream? 2)The model is overparametrized? Should I have to fixed parameters? (I have over one hundred couple of kinetics with 5-7 observations for each) I would really appreciate aany advice, thanks. Christian
Jul 22, 2009 Christian Woloch Dynamic enzymatic model
Jul 22, 2009 Ekaterina Gibiansky RE: Dynamic enzymatic model
Jul 22, 2009 Saik Urien Svp Re: Dynamic enzymatic model
Jul 31, 2009 Ekaterina Gibiansky FW: Dynamic enzymatic model