RE: Interindividual variability in residual variance

From: Mats Karlsson Date: July 12, 2007 technical Source: mail-archive.com
Dear Alison, The addition of EXP(ETA(.)) is to provide a scaling for the residual error magnitude. This scaling factor is 1 for the typical individual (ETA=0) and the sigma estimate is thus the residual error magnitude for the typical subject. Other subjects will have scaling factors larger or smaller than 1, but all will be >0. I see no problem in the "exp of exp" - it does exactly what is desired. With the alternative model Y = LOG(F) + ETA(.)*EPS(1) the typical individual (with ETA=0) is having a zero residual error magnitude. Clearly that model does not work. Best regards, Mats Mats Karlsson, PhD Professor of Pharmacometrics Div. of Pharmacokinetics and Drug Therapy Dept. of Pharmaceutical Biosciences Faculty of Pharmacy Uppsala University Box 591 SE-751 24 Uppsala Sweden phone +46 18 471 4105 fax +46 18 471 4003 [EMAIL PROTECTED]
Quoted reply history
-----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Alison Boeckmann Sent: Thursday, July 12, 2007 02:04 To: Samtani, Mahesh [PRDUS]; [email protected] Subject: Re: [NMusers] Interindividual variability in residual variance 1) The original email and responses can be found at http://www.cognigencorp.com/nonmem/nm/99feb172004.html 2) Your model does not make sense. In effect Y = LOG(F) + EXP(ETA(.))*EPS(1) This is equivalent to EXP(Y)=EXP(LOG(F))*EXP(EXP(ETA(.))*EPS(1)) EXP(Y)=F*EXP(EXP(ETA(.))*EPS(1)) Note the exp of exp. When working with logs,an additive error term makes more sense Y = LOG(F) + ETA(.)*EPS(1) LOG(Y)=EXP(LOG(F) + ETA(.)*EPS(1))=EXP(LOG(F))*EXP(ETA(.)*EPS(1)) LOG(Y)=F*EXP(ETA(.)*EPS(1)) This is now a proportional error model. On Wed, 11 Jul 2007 08:26:54 -0400, "Samtani, Mahesh [PRDUS]" <[EMAIL PROTECTED]> said: > Dear NMusers,<?xml:namespace prefix = o ns = > "urn:schemas-microsoft-com:office:office" /> > > I have run in to an old problem that Vladimir once described here on the > users net. I am trying to implement inter-individual variability in > residual variance and the corresponding OMEGA is not being iterated. > Usually, in Dr. Karlsson's work this error structure is implemented on a > proportional or proportional+additive EPS model. I am wondering if my > problem is because I am trying to implement ETA on EPS using the > transform both sides approach as follows? > > > > $ERROR > > CALLFL=0 > > IPRED = -5 > > IF (F.GT.0) IPRED = LOG(F) > > IRES=DV-IPRED > > W=1 > > IWRES=IRES/W > > Y = IPRED + EXP(ETA(.))*EPS(1) > > > > Kindly advice...MNS > > > > --------Cut here > > From: "Piotrovskij, Vladimir [PRDBE]" - [EMAIL PROTECTED] > > Subject: [NMusers] Implementation of interindividual variability in > residual variance > > Date: 2/17/2004 9:37 AM > > > > Dear NONMEM users, > > > > I am trying to implement an interidividual variability in > > the residual variance using an additional random effect: > > > > $ERR > > Y = F + EXP(ETA(.))*EPS(1) > > > > It turned out the corresponding OMEGA was not iterated, and the final > estimate > > did not differ from the initial value. Below is an example control stream > > and the output illustrating the problem (Note, the actual model I work > with is more complicated). > > > > Thanks in advance. > > > > Best regards, > > Vladimir > > --------Cut here > > -- Alison Boeckmann [EMAIL PROTECTED]
Jul 11, 2007 Mahesh Samtani Interindividual variability in residual variance
Jul 11, 2007 Erik Olofsen RE: Interindividual variability in residual variance
Jul 11, 2007 Mats Karlsson RE: Interindividual variability in residual variance
Jul 12, 2007 Alison Boeckmann Re: Interindividual variability in residual variance
Jul 12, 2007 Mats Karlsson RE: Interindividual variability in residual variance
Jul 13, 2007 Alison Boeckmann RE: Interindividual variability in residual variance